[quote]

特別注意兩點(diǎn) 一個(gè)是where 的用法

group的用法

case when的用法

這個(gè)對(duì)string的比較 是單引號(hào) 括起test后面的整串， 然后 == 然后雙引號(hào)括起比較的字符串內(nèi)容

[/quote]

[quote]

resultType="com.zyd.orders.placeorder.model.SalesmanDO">

select T.salesmanId,T.salesmanCode, T.salesmanName, T.idNo,T.idType,T.phoneNo, T.channelId,T.registerDate, T.profession, T.email,

T.sumLoanAppCount, T.sumInProgressCount, T.sumFailLoanCount,T.sumReleaseCount,T.sumReleaseAmount ,T.channelName

from

(SELECT

s.salesman_id as salesmanId,

s.salesman_code as salesmanCode,

s.salesman_name as salesmanName,

s.id_no as idNo,

s.id_type as idType,

s.phone_no as phoneNo,

s.channel_id as channelId,

s.register_date as registerDate,

s.profession as profession,

s.email as email,

s.login_total_times,

count(case when ob.apply_status > 0 then ob.apply_status end) as sumLoanAppCount,

count(case when ob.apply_status > 1 and ob.apply_status < 6 then ob.apply_status end) as sumInProgressCount,

count(case when ob.apply_status = 7 then ob.apply_status end) as sumFailLoanCount,

count(case when ob.release_status = 1 then ob.release_status end) as sumReleaseCount,

sum(case when ob.release_status = 1 then ob.release_money end) as sumReleaseAmount,

c.channel_name as channelName

from salesman s left join order_base ob

on s.salesman_id = ob.user_id

left join channel_vendor c

on s.channel_id = c.channel_id

AND s.salesman_id = #{salesmanId}

AND s.phone_no = #{phoneNo}

AND s.password = #{password}

AND s.salesman_name = #{salesmanName}

AND s.id_no = #{idNo}

AND s.card_no = #{cardNo}

AND ob.id = #{loanApplicationCode}

AND s.register_date >= #{registerBeginDate}

AND s.register_date <= #{registerEndDate}

group by s.salesman_id,s.salesman_code,s.salesman_name,s.id_no,s.id_type,s.phone_no,s.channel_id,s.register_date,s.profession,s.email,s.login_total_times

) T

AND T.sumLoanAppCount > 0

[/quote]

[quote]

select * from (

SELECT

s.salesman_id as salesmanId,

s.salesman_name as salesmanName,

s.id_no as idNo,

s.id_type as idType,

s.phone_no as phoneNo,

s.channel_id as channelId,

s.register_date as registerDate,

s.profession as profession,

s.email as email,

count(case when ob.apply_status = 7 then ob.apply_status else 0 end) as reject_count,

count(case when ob.apply_status > 1 and ob.apply_status < 6 then ob.apply_status else 0 end) as inprogress_count,

count(case when ob.apply_status > 0 then ob.apply_status else 0 end) as total_count,

count(case when ob.release_status = 1 then ob.apply_status else 0 end) as release_status,

sum(case when ob.release_status = 1 then ob.release_money else 0 end) as total_release_amt

from salesman s left join order_base ob

on s.salesman_id = ob.user_id

where s.salesman_id = 1

group by s.salesman_id,s.salesman_name,s.id_no,s.id_type,s.phone_no,s.channel_id,s.register_date,s.profession,s.email

) t

[/quote]

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