?? ? ? ?///?<summary>
????????///?按最大字節(jié)數(shù),截取字符串
????????///?</summary>
????????///?<param?name="value">要截取的字符串</param>
????????///?<param?name="length">最大長度</param>
????????///?<returns></returns>
????????private?string?Intercept(string?value,?int?length)
????????{
????????????if?(value.Length?*?2?<=?length)
????????????{
????????????????return?value;
????????????}
????????????string?newvalue;
????????????for?(int?i?=?length?/?2;?i?<?value.Length;?i++)
????????????{
????????????????newvalue?=?value.Substring(0,?i);
????????????????if?(Encoding.Default.GetByteCount(newvalue)?>?length)
????????????????{
????????????????????return?value.Substring(0,?i?-?1);
????????????????}
????????????}
????????????return?value;
????????}

?

正確替換多個匹配內(nèi)容

private?void?button1_Click(object?sender,?EventArgs?e)
{
????Regex?regx?=?new?Regex(@"\[image\]",?RegexOptions.IgnoreCase);
????string?content?=?textBox1.Text;
???
????Match?m?=?regx.Match(content);
????while?(m.Success)
????{
????????content?=?content.Remove(m.Index,?m.Value.Length);
????????content?=?content.Insert(m.Index,?"[picture]");
????????m?=?regx.Match(content);

????}

????textBox2.Text?=?content;
}

?方法二:

private?void?button1_Click(object?sender,?EventArgs?e)
{
????Regex?regx?=?new?Regex(@"\[image\]",?RegexOptions.IgnoreCase);
????string?content?=?textBox1.Text;
????content=regx.Replace(content,?new?MatchEvaluator(DoMatch));?
????textBox2.Text?=?content;
}

private?string?DoMatch(Match?m)
{
????return?"[picture]";
}

?

function fmt(s) {var value = s.replace(/,/g, "");var v = value.replace(/(\d+)(\.\d+)?/, "$1");var d = value.replace(/(\d+)(\.\d+)?/, "$2");var reg = /\d{4,}\b/;while (reg.test(v)) {v = v.replace(/(\d{3})\b/, ',$1');}return v + d; ;}

?

轉(zhuǎn)載于:https://www.cnblogs.com/gateluck/archive/2010/12/21/1913056.html

與50位技術(shù)專家面對面20年技術(shù)見證，附贈技術(shù)全景圖

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