https://codeforces.com/contest/1133/problem/B

題解：對于一個數a[i]直接mod k，然后桶排序思想，暴力枚舉?

/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int using namespace std; typedef long long ll; //typedef __int128 lll; const int N=200000+10; const int M=100000+10; const int MOD=1e9+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,q; int ans,cnt,flag,temp,sum; int a[N]; int b[N]; char str; struct node{}; int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endif//ios::sync_with_stdio(false);//cin.tie(0);//cout.tie(0);//scanf("%d",&t);//while(t--){scanf("%d%d",&n,&k);for(int i=1;i<=n;i++){scanf("%d",&a[i]);b[a[i]%k]++;}for(int i=0;i<=100;i++){for(int j=i;j<=100;j++){if((i+j)%k==0&&b[i]>0&&b[j]>0){if(i==j){ans+=b[i]/2*2;b[i]=b[i]-b[i]/2*2;continue;}int minl=min(b[i],b[j]);b[i]-=minl;b[j]-=minl;ans+=2*minl;//cout<<i<<j<<endl;}}}cout<<ans<<endl;//}#ifdef DEBUGprintf("Time cost : %lf s\n",(double)clock()/CLOCKS_PER_SEC); #endif//cout << "Hello world!" << endl;return 0; }

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