666RPG
https://ac.nowcoder.com/acm/contest/373/B
C++版本一
題解:DP
/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int using namespace std; typedef long long ll; //typedef __int128 lll; const int N=1000000+10; const int MOD=1e8+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,q; int ans,cnt,flag,temp; char str; ll dp[2][N];int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endifscanf("%d",&n);//scanf("%d",&t);//while(t--){}int t=1;int s=0;int zero=(N>>1);int limit=n*666;dp[1][zero]=1;for(int i=1;i<=n;i++){scanf("%d",&k);for(int j=zero-limit;j<=zero+limit;j++){dp[s][j]=0;}for(int j=zero-limit;j<=zero+limit;j++){if(dp[t][j]){dp[s][j+k]=(dp[s][j+k]+dp[t][j])%MOD;dp[s][zero+666]=0;dp[s][2*zero-j]=(dp[s][2*zero-j]+dp[t][j])%MOD;dp[s][zero+666]=0;}}t^=1;s^=1;}cout << dp[t][zero-666] << endl;//cout << "Hello world!" << endl;return 0; }?
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