a+b+c+d=?
https://ac.nowcoder.com/acm/contest/338/G
題解:2的63冪剛剛好爆ll,那就祭出__int128吧
/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int using namespace std; typedef long long ll; typedef __int128 lll; const int N=100000+10; const int MOD=1e9+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; ll t,n,m,k,q,ans; char str; void print(__int128 x) {if(x<0){print("-");x=-x;}if (x>9) print(x/10);putchar('0'+x%10); } int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endifwhile(~scanf("%lld",&t)){ll a,b,c,d;while(t--){scanf("%lld%lld%lld%lld",&a,&b,&c,&d);lll ans=(lll)a+(lll)b+(lll)c+(lll)d;print(ans);cout << endl;}}//cout << "Hello world!" << endl;return 0; }?
總結
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