Dandan's lunch
生活随笔
收集整理的這篇文章主要介紹了
Dandan's lunch
小編覺得挺不錯的,現在分享給大家,幫大家做個參考.
https://ac.nowcoder.com/acm/contest/338/D
題解:計算一下面積,排序
參考文章:https://blog.csdn.net/weixin_43272781/article/details/85800560
/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int using namespace std; typedef long long ll; //typedef __int128 lll; const int N=100000+10; const int MOD=1e9+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,q,ans; int a[N]; ll b[N]; char str; ll x[3]; ll y[3]; ll S(){return labs(x[0]*y[1]+x[1]*y[2]+x[2]*y[0]-x[0]*y[2]-x[1]*y[0]-x[2]*y[1]);} int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endifscanf("%d",&n);for(int i=1;i<=n;i++){scanf("%d%lld%lld%lld%lld%lld%lld",&q,&x[0],&y[0],&x[1],&y[1],&x[2],&y[2]);a[i]=q;b[i]=S();}k=a[1];sort(a+1,a+n+1);sort(b+1,b+n+1);ans=lower_bound(a+1,a+n+1,k)-a;cout << b[ans] << endl;//cout << "Hello world!" << endl;return 0; }?
總結
以上是生活随笔為你收集整理的Dandan's lunch的全部內容,希望文章能夠幫你解決所遇到的問題。
- 上一篇: Sleepy Kaguya
- 下一篇: a+b+c+d=?