@eq2=str2sym(‘a(chǎn)i+bj=5’);
eq3=str2sym(‘a(chǎn)i-bj=1’);
for i=1:2
for j=1:6
[a,b]=solve(eq2,eq3);
eq2=subs(subs(eq2,‘i’,i),‘j’,j);
eq3=subs(subs(eq3,‘i’,i),‘j’,j);
jieguo1(i,j,1:2)=double([a b]);
end
end
沒有進(jìn)入循環(huán)和替換 不知道那個(gè)地方出錯(cuò)了，小白求解答

計(jì)算結(jié)果顯示的是
val(:,:,1) =

1 至 2 列

0.000000000000000e+00 - 3.000000000000000e+00i 0.000000000000000e+00 - 3.000000000000000e+00i0.000000000000000e+00 - 3.000000000000000e+00i 0.000000000000000e+00 - 3.000000000000000e+00i

3 至 4 列

0.000000000000000e+00 - 3.000000000000000e+00i 0.000000000000000e+00 - 3.000000000000000e+00i0.000000000000000e+00 - 3.000000000000000e+00i 0.000000000000000e+00 - 3.000000000000000e+00i

5 至 6 列

0.000000000000000e+00 - 3.000000000000000e+00i 0.000000000000000e+00 - 3.000000000000000e+00i0.000000000000000e+00 - 3.000000000000000e+00i 0.000000000000000e+00 - 3.000000000000000e+00i

val(:,:,2) =

1 至 2 列

0.000000000000000e+00 - 2.000000000000000e+00i 0.000000000000000e+00 - 2.000000000000000e+00i0.000000000000000e+00 - 2.000000000000000e+00i 0.000000000000000e+00 - 2.000000000000000e+00i

3 至 4 列

0.000000000000000e+00 - 2.000000000000000e+00i 0.000000000000000e+00 - 2.000000000000000e+00i0.000000000000000e+00 - 2.000000000000000e+00i 0.000000000000000e+00 - 2.000000000000000e+00i

5 至 6 列

0.000000000000000e+00 - 2.000000000000000e+00i 0.000000000000000e+00 - 2.000000000000000e+00i0.000000000000000e+00 - 2.000000000000000e+00i 0.000000000000000e+00 - 2.000000000000000e+00i

總結(jié)

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