/*找人,找到輸出在第幾樓第幾號房間（考慮沒有找到的情況）*/ /*{{"鳳姐","蔡除坤","張潔"},{"姚鳴","芙蓉姐姐"},{"馬爾克死","打仲馬","肝塞特","高死你"}};*/ import java.util.*; public class B {public static void main(String[]args){Scanner input=new Scanner(System.in);String arr[][] = {{"鳳姐","蔡除坤","張潔"},{"姚鳴","芙蓉姐姐"},{"馬爾克死","打仲馬","肝塞特","高死你"}};/*好考慮沒有找到*/boolean b = false;for(int i = 0; i<arr.length; i++){for(int j = 0; j < arr[i].length; j++){System.out.print(arr[i][j] + " ");}}System.out.print("\n");System.out.println("Who is you need to look for?");String name = input.next();for(int i = 0; i<arr.length; i++){for(int j=0; j<arr[i].length; j++){if(name.equals(arr[i][j])){b=true;//賦值，滿足條件，找到System.out.println(name+"在第"+(i+1)+"樓第"+(j+1)+"個號房間");break;}}}} }

總結

以上是生活随笔為你收集整理的简单的二维数组的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。