int a[5]={}, a+1与(int*)a+1的区别
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int a[5]={}, a+1与(int*)a+1的区别
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/*int a[5]={}, &a+1與(int*)a+1的區別
*/
#include <stdio.h>int main()
{int b, *pb;char *pb2;pb = &b + 1;pb2 = (char*)&b + sizeof(b);printf("&b=%#x, pb=%#x, pb2=%#x\n", &b, pb, pb2);printf("Equal=%d\n", (void*)pb == (void*)pb2 );int a[5]={1,2,3,4,5}, *pa;char *pa2;pa = (int*)(&a + 1);pa2 = (char*)&a + sizeof(a);printf("\nDiff: &a=%#x, %#x, %#x\n", &a, (int*)&a + 1, &a + 1); // 兩者是有區別的printf("&a=%#x, pa=%#x, pa2=%#x\n", &a, pa, pa2);printf("Equal2=%d\n", (void*)pa == (void*)pa2 );puts("結論: &a + 1 == (char*)&a + sizeof(a)\n");return 0;
}
運行情況:
[zcm@socket #40]$make gcc -o a a.c [zcm@socket #41]$./a &b=0x22ac7c, pb=0x22ac80, pb2=0x22ac80 Equal=1Diff: &a=0x22ac68, 0x22ac6c, 0x22ac7c &a=0x22ac68, pa=0x22ac7c, pa2=0x22ac7c Equal2=1 結論: &a + 1 == (char*)&a + sizeof(a)[zcm@socket #42]$總結
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