mysql首字母大写函数_string - 首字母大写。MySQL的
string - 首字母大寫。MySQL的
在MySQL的說法中,有沒有人知道這個TSQL的等價物?
我想把每個條目的第一個字母大寫。
UPDATE tb_Company SET CompanyIndustry = UPPER(LEFT(CompanyIndustry, 1))
+ SUBSTRING(CompanyIndustry, 2, LEN(CompanyIndustry))
Chin asked 2019-08-12T13:56:08Z
13個解決方案
237 votes
它幾乎相同,你只需要更改為使用CONCAT()函數而不是+運算符:
UPDATE tb_Company
SET CompanyIndustry = CONCAT(UCASE(LEFT(CompanyIndustry, 1)),
SUBSTRING(CompanyIndustry, 2));
這將轉hello到Hello,wOrLd到WOrLd,BLABLA到BLABLA等。如果你想要大寫第一個字母和小寫另一個,你只需要使用LCASE函數:
UPDATE tb_Company
SET CompanyIndustry = CONCAT(UCASE(LEFT(CompanyIndustry, 1)),
LCASE(SUBSTRING(CompanyIndustry, 2)));
請注意,UPPER和UCASE做同樣的事情。
Vincent Savard answered 2019-08-12T13:56:37Z
38 votes
Vincents對大寫第一封信的出色回答非常適用于整個列字符串的首字母大寫。
但是,如果你想在表格列的字符串中大寫字母的第一個字母怎么辦?
例如:"阿比維爾高中"
我還沒有在Stackoverflow中找到答案。 我不得不拼湊一些我在谷歌找到的答案,為上面的例子提供了可靠的解決方案。 它不是本機功能,而是用戶創建的MySQL版本5+允許的功能。
如果您在MySQL上擁有Super / Admin用戶狀態或者在您自己的計算機上安裝了本地mysql,您可以創建一個FUNCTION(如存儲過程),它位于您的數據庫中,并且可以在以后的所有SQL查詢中使用。 D b。
我創建的函數允許我使用這個我稱之為" UC_Words" 就像MySQL的內置本機函數一樣,這樣我就可以像這樣更新一個完整的列:
UPDATE Table_name
SET column_name = UC_Words(column_name)
要插入功能代碼,我在創建函數時更改了MySQL標準分隔符(;),然后在函數創建腳本之后將其重置為正常。 我個人也希望輸出也是UTF8 CHARSET。
功能創建=
DELIMITER ||
CREATE FUNCTION `UC_Words`( str VARCHAR(255) ) RETURNS VARCHAR(255) CHARSET utf8_general_ci
BEGIN
DECLARE c CHAR(1);
DECLARE s VARCHAR(255);
DECLARE i INT DEFAULT 1;
DECLARE bool INT DEFAULT 1;
DECLARE punct CHAR(17) DEFAULT ' ()[]{},.-_!@;:?/';
SET s = LCASE( str );
WHILE i < LENGTH( str ) DO
BEGIN
SET c = SUBSTRING( s, i, 1 );
IF LOCATE( c, punct ) > 0 THEN
SET bool = 1;
ELSEIF bool=1 THEN
BEGIN
IF c >= 'a' AND c <= 'z' THEN
BEGIN
SET s = CONCAT(LEFT(s,i-1),UCASE(c),SUBSTRING(s,i+1));
SET bool = 0;
END;
ELSEIF c >= '0' AND c <= '9' THEN
SET bool = 0;
END IF;
END;
END IF;
SET i = i+1;
END;
END WHILE;
RETURN s;
END ||
DELIMITER ;
這適用于輸出字符串中多個單詞的大寫首字母。
假設您的MySQL登錄用戶名具有足夠的權限 - 如果沒有,并且您無法在個人計算機上設置臨時數據庫來轉換表格,請詢問您的共享主機提供商是否為您設置此功能。
Martin Sansone - MiOEE answered 2019-08-12T13:58:24Z
17 votes
您可以使用UCASE(),MID()和CONCAT()的組合:
SELECT CONCAT(UCASE(MID(name,1,1)),MID(name,2)) AS name FROM names;
Wouter Dorgelo answered 2019-08-12T13:58:52Z
8 votes
mysql> SELECT schedule_type AS Schedule FROM ad_campaign limit 1;
+----------+
| Schedule |
+----------+
| ENDDATE |
+----------+
1 row in set (0.00 sec)
mysql> SELECT CONCAT(UCASE(MID(schedule_type,1,1)),LCASE(MID(schedule_type,2))) AS Schedule FROM ad_campaign limit 1;
+----------+
| Schedule |
+----------+
| Enddate |
+----------+
1 row in set (0.00 sec)
[http://dev.mysql.com/doc/refman/5.0/en/string-functions.html#function_mid]
Root answered 2019-08-12T13:59:25Z
5 votes
[http://forge.mysql.com/tools/tool.php?id=201]
如果列中有多個單詞,則此操作將不起作用,如下所示。在這種情況下,上面提到的UDF可能有所幫助。
mysql> select * from names;
+--------------+
| name |
+--------------+
| john abraham |
+--------------+
1 row in set (0.00 sec)
mysql> SELECT CONCAT(UCASE(MID(name,1,1)),MID(name,2)) AS name FROM names;
+--------------+
| name |
+--------------+
| John abraham |
+--------------+
1 row in set (0.00 sec)
或許這個會有所幫助......
[https://github.com/mysqludf/lib_mysqludf_str#str_ucwords]
shantanuo answered 2019-08-12T14:00:20Z
2 votes
這很好用。
UPDATE狀態SET name = CONCAT(UCASE(LEFT(name,1)),??????????????????????????????? LCASE(SUBSTRING(name,2)));
Abhinav Sahu answered 2019-08-12T14:00:55Z
1 votes
UPDATE tb_Company SET CompanyIndustry = UCASE(LEFT(CompanyIndustry, 1)) +
SUBSTRING(CompanyIndustry, 2, LEN(CompanyIndustry))
Jasdeep Singh answered 2019-08-12T14:01:14Z
1 votes
創造一個功能:
CREATE DEFINER=`root`@`localhost` FUNCTION `UC_FIRST`(`oldWord` VARCHAR(255))
RETURNS varchar(255) CHARSET utf8
RETURN CONCAT( UCASE( LEFT(oldWord, 1)), LCASE(SUBSTRING(oldWord, 2)))
使用功能
UPDATE tbl_name SET col_name = UC_FIRST(col_name);
Florin answered 2019-08-12T14:01:49Z
1 votes
如果有人試圖將每個單詞用空格分開...
CREATE FUNCTION response(name VARCHAR(40)) RETURNS VARCHAR(200) DETERMINISTIC
BEGIN
set @m='';
set @c=0;
set @l=1;
while @c <= char_length(name)-char_length(replace(name,' ','')) do
set @c = @c+1;
set @p = SUBSTRING_INDEX(name,' ',@c);
set @k = substring(name,@l,char_length(@p)-@l+1);
set @l = char_length(@k)+2;
set @m = concat(@m,ucase(left(@k,1)),lcase(substring(@k,2)),' ');
end while;
return trim(@m);
END;
CREATE PROCEDURE updateNames()
BEGIN
SELECT response(name) AS name FROM names;
END;
結果
+--------------+
| name |
+--------------+
| Abdul Karim |
+--------------+
Jahir islam answered 2019-08-12T14:02:19Z
0 votes
這應該很好地工作:
UPDATE tb_Company SET CompanyIndustry =
CONCAT(UPPER(LEFT(CompanyIndustry, 1)), SUBSTRING(CompanyIndustry, 2))
Chris Hutchinson answered 2019-08-12T14:02:59Z
0 votes
UPDATE users
SET first_name = CONCAT(UCASE(LEFT(first_name, 1)),
LCASE(SUBSTRING(first_name, 2)))
,last_name = CONCAT(UCASE(LEFT(last_name, 1)),
LCASE(SUBSTRING(last_name, 2)));
sandeep kumar answered 2019-08-12T14:03:20Z
0 votes
select CONCAT(UCASE(LEFT('CHRIS', 1)),SUBSTRING(lower('CHRIS'),2));
上述聲明可用于首字母CAPS,其余為小寫。
Aamir Khan answered 2019-08-12T14:03:50Z
-1 votes
Uso algo simples assim;)
DELIMITER $$
DROP FUNCTION IF EXISTS `uc_frist` $$
CREATE FUNCTION `uc_frist` (str VARCHAR(200)) RETURNS varchar(200)
BEGIN
set str:= lcase(str);
set str:= CONCAT(UCASE(LEFT(str, 1)),SUBSTRING(str, 2));
set str:= REPLACE(str, ' a', ' A');
set str:= REPLACE(str, ' b', ' B');
set str:= REPLACE(str, ' c', ' C');
set str:= REPLACE(str, ' d', ' D');
set str:= REPLACE(str, ' e', ' E');
set str:= REPLACE(str, ' f', ' F');
set str:= REPLACE(str, ' g', ' G');
set str:= REPLACE(str, ' h', ' H');
set str:= REPLACE(str, ' i', ' I');
set str:= REPLACE(str, ' j', ' J');
set str:= REPLACE(str, ' k', ' K');
set str:= REPLACE(str, ' l', ' L');
set str:= REPLACE(str, ' m', ' M');
set str:= REPLACE(str, ' n', ' N');
set str:= REPLACE(str, ' o', ' O');
set str:= REPLACE(str, ' p', ' P');
set str:= REPLACE(str, ' q', ' Q');
set str:= REPLACE(str, ' r', ' R');
set str:= REPLACE(str, ' s', ' S');
set str:= REPLACE(str, ' t', ' T');
set str:= REPLACE(str, ' u', ' U');
set str:= REPLACE(str, ' v', ' V');
set str:= REPLACE(str, ' w', ' W');
set str:= REPLACE(str, ' x', ' X');
set str:= REPLACE(str, ' y', ' Y');
set str:= REPLACE(str, ' z', ' Z');
return str;
END $$
DELIMITER ;
Hton answered 2019-08-12T14:04:20Z
總結
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