將list中的元素按奇偶分到兩個(gè)deque中

Practice 9.20

#include <iostream> #include <string> #include <vector> #include <algorithm> #include <list> #include <iterator> #include <cmath> #include <deque> #include <cstring> #include <forward_list> using namespace std;void fun(list<int> lst, deque<int> & q1, deque<int> & q2) {for(auto i : lst) {if(i&1) {q1.push_back(i);}else {q2.push_back(i);}} }void print(deque<int> deq) {for(auto i : deq) {cout << i << " ";}cout << endl; }int main() {list<int> ilst = {0, 1, 2, 3, 4, 5, 6, 7, 8};deque<int> ideq1;deque<int> ideq2;fun(ilst, ideq1, ideq2);cout << "This is deque_1: " << endl;print(ideq1);cout << "This is deque_2: " << endl;print(ideq2);return 0; }

Outpt

This is deque_1: 1 3 5 7 This is deque_2: 0 2 4 6 8

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