can you pass variadic arguments after named parameters?

Python 3.4.3：答案是肯定的.

如果要調(diào)用僅命名固定參數(shù)的函數(shù),請將可變參數(shù)放在函數(shù)定義中

def function(*args, bob, sally):

print(args, bob, sally)

values = [1, 2, 3, 4]

function(bob="Hi bob", sally="Hello sally", *values)

function(*values, bob="Hi bob", sally="Hello sally")

function(bob="Hi bob", *values, sally="Hello sally")

產(chǎn)生

(1, 2, 3, 4) Hi bob Hello sally

(1, 2, 3, 4) Hi bob Hello sally

(1, 2, 3, 4) Hi bob Hello sally

如您所見,您可以調(diào)用函數(shù)以您喜歡的任何順序放置參數(shù).

由于您明確地引用了實例方法,因此如果函數(shù)是一種方法(比如A類),則值得檢查會發(fā)生什么

class A():

def function(self, *args, bob, sally):

print(args, bob, sally)

values = [1, 2, 3, 4]

a=A()

a.function(bob="Hi bob", sally="Hello sally", *values)

a.function(*values, bob="Hi bob", sally="Hello sally")

a.function(bob="Hi bob", *values, sally="Hello sally")

仍在工作和生產(chǎn)

(1, 2, 3, 4) Hi bob Hello sally

(1, 2, 3, 4) Hi bob Hello sally

(1, 2, 3, 4) Hi bob Hello sally

Python 2.7.6：答案是否定的.

>>> def function(*args, bob, sally):

File "", line 1

def function(*args, bob, sally):

^

SyntaxError: invalid syntax

另一種方法可以是為可變參數(shù)賦予名稱

values = {'p1': 1, 'p2': 2, 'p3': 3, 'p4': 4}

然后你可以定義

def function(bob, sally, **kwargs):

print(kwargs['p1'])

并稱之為

function(bob="Hi bob", sally="Hello sally", **values)

總結

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