Sql存储过程加密和解密
可用于加密SQL存儲過程或者觸發器(這是SQL Server本身提供的,也就是說這是微軟的加密算法) http://www.mscto.com 使用 WITH ENCRYPTION 選項 WITH ENCRYPTION 子句對用戶隱藏存儲過程的文本。下例創建加密過程,使用 sp_helptext 系統存儲過程獲取關于加密過程的信息,然后嘗試直接從 syscomments 表中獲取關于該過程的信息。 IF EXISTS (Select name FROM sysobjects Where name = 'encrypt_this' AND type = 'P') Drop PROCEDURE encrypt_this GO USE pubs GO Create PROCEDURE encrypt_this WITH ENCRYPTION AS Select * FROM authors GO 軟件開發網 EXEC sp_helptext encrypt_this http://www.mscto.com 下面是結果集: The object's comments have been encrypted. 接下來,選擇加密存儲過程內容的標識號和文本。 Select c.id, c.text FROM syscomments c INNER JOIN sysobjects o ON c.id = o.id Where o.name = 'encrypt_this' 下面是結果集: 說明 text 列的輸出顯示在單獨一行中。執行時,該信息將與 id 列信息出現在同一行中。 Id text ---------- ------------------------------------------------------------ 1413580074 ?????????????????????????????????e?????????????????????????????????????????????????????????????????????????? (1 row(s) affected) 備注: create proc name with encryption as begin --語句 end Create TRIGGER trigger_name ON { table | view } WITH ENCRYPTION FOR Update AS begin --語句 end Sql存儲過程解密算法 破解微軟的加密算法網上同樣有很多的Sql存儲過程的解密軟件,但大都是收費的。下邊是網上流傳的Sql存儲過程解密算法,雖非官方,但絕對可行!同樣可用于解密SQL存儲過程或者觸發器。 create PROCEDURE sp_decrypt(@objectname varchar(50)) AS begin set nocount on --CSDN:j9988 copyright:2004.07.15 --V3.2 --破解字節不受限制,適用于SQLSERVER2000存儲過程,函數,視圖,觸發器 --修正上一版\"視圖觸發器\"不能正確解密錯誤 --發現有錯,請E_MAIL:CSDNj9988@tom.com begin tran declare @objectname1 varchar(100),@orgvarbin varbinary(8000) declare @sql1 nvarchar(4000),@sql2 varchar(8000),@sql3 nvarchar(4000),@sql4 nvarchar(4000) DECLARE @OrigSpText1 nvarchar(4000), @OrigSpText2 nvarchar(4000) , @OrigSpText3 nvarchar(4000), @resultsp nvarchar(4000) declare @i int,@status int,@type varchar(10),@parentid int declare @colid int,@n int,@q int,@j int,@k int,@encrypted int,@number int select @type=xtype,@parentid=parent_obj from sysobjects where id=object_id(@objectname) http://www.mscto.com create table #temp(number int,colid int,ctext varbinary(8000),encrypted int,status int) insert #temp Select number,colid,ctext,encrypted,status FROM syscomments Where id = object_id(@objectname) select @number=max(number) from #temp set @k=0 http://www.mscto.com while @k<=@number begin if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k) begin if @type='P' set @sql1=(case when @number>1 then 'Alter PROCEDURE '+ @objectname +';'+rtrim(@k)+' WITH ENCRYPTION AS ' else 'Alter PROCEDURE '+ @objectname+' WITH ENCRYPTION AS ' end) if @type='TR' begin declare @parent_obj varchar(255),@tr_parent_xtype varchar(10) select @parent_obj=parent_obj from sysobjects where id=object_id(@objectname) select @tr_parent_xtype=xtype from sysobjects where id=@parent_obj if @tr_parent_xtype='V' begin set @sql1='Alter TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTERD OF Insert AS PRINT 1 ' end else begin set @sql1='Alter TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR Insert AS PRINT 1 ' end end if @type='FN' or @type='TF' or @type='IF' set @sql1=(case @type when 'TF' then 'Alter FUNCTION '+ @objectname+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end ' when 'FN' then 'Alter FUNCTION '+ @objectname+'(@a char(1)) returns char(1) with encryption as begin return @a end' when 'IF' then 'Alter FUNCTION '+ @objectname+'(@a char(1)) returns table with encryption as return select @a as a' end) 軟件開發網 if @type='V' set @sql1='Alter VIEW '+@objectname+' WITH ENCRYPTION AS Select 1 as f' set @q=len(@sql1) set @sql1=@sql1+REPLICATE('-',4000-@q) select @sql2=REPLICATE('-',8000) set @sql3='exec(@sql1' select @colid=max(colid) from #temp where number=@k set @n=1 while @n<=CEILING(1.0*(@colid-1)/2) and len(@sql3)<=3996 begin set @sql3=@sql3+'+@' set @n=@n+1 end set @sql3=@sql3+')' exec sp_executesql @sql3,N'@sql1 nvarchar(4000),@ varchar(8000)',@sql1=@sql1,@=@sql2 end set @k=@k+1 end set @k=0 while @k<=@number begin if exists(select 1 from syscomments where id=object_id(@objectname) and number=@k) begin select @colid=max(colid) from #temp where number=@k set @n=1 http://www.mscto.com while @n<=@colid begin select @OrigSpText1=ctext,@encrypted=encrypted,@status=status FROM #temp Where colid=@n and number=@k SET @OrigSpText3=(Select ctext FROM syscomments Where id=object_id(@objectname) and colid=@n and number=@k) if @n=1 begin if @type='P' SET @OrigSpText2=(case when @number>1 then 'Create PROCEDURE '+ @objectname +';'+rtrim(@k)+' WITH ENCRYPTION AS ' else 'Create PROCEDURE '+ @objectname +' WITH ENCRYPTION AS ' end) if @type='FN' or @type='TF' or @type='IF' SET @OrigSpText2=(case @type when 'TF' then 'Create FUNCTION '+ @objectname+'(@a char(1)) returns @b table(a varchar(10)) with encryption as begin insert @b select @a return end ' when 'FN' then 'Create FUNCTION '+ @objectname+'(@a char(1)) returns char(1) with encryption as begin return @a end' when 'IF' then 'Create FUNCTION '+ @objectname+'(@a char(1)) returns table with encryption as return select @a as a' end) if @type='TR' begin if @tr_parent_xtype='V' begin set @OrigSpText2='Create TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION INSTEAD OF Insert AS PRINT 1 ' end else begin set @OrigSpText2='Create TRIGGER '+@objectname+' ON '+OBJECT_NAME(@parentid)+' WITH ENCRYPTION FOR Insert AS PRINT 1 ' end end if @type='V' set @OrigSpText2='Create VIEW '+@objectname+' WITH ENCRYPTION AS Select 1 as f' set @q=4000-len(@OrigSpText2) set @OrigSpText2=@OrigSpText2+REPLICATE('-',@q) end else begin SET @OrigSpText2=REPLICATE('-', 4000) end SET @i=1 SET @resultsp = replicate(N'A', (datalength(@OrigSpText1) / 2)) http://www.mscto.com WHILE @i<=datalength(@OrigSpText1)/2 BEGIN SET @resultsp = stuff(@resultsp, @i, 1, NCHAR(UNICODE(substring(@OrigSpText1, @i, 1)) ^ (UNICODE(substring(@OrigSpText2, @i, 1)) ^ UNICODE(substring(@OrigSpText3, @i, 1))))) SET @i=@i+1 END set @orgvarbin=cast(@OrigSpText1 as varbinary(8000)) set @resultsp=(case when @encrypted=1 then @resultsp else convert(nvarchar(4000),case when @status&2=2 then uncompress(@orgvarbin) else @orgvarbin end) end) print @resultsp set @n=@n+1 end end set @k=@k+1 end drop table #temp rollback tran end go 軟件開發網
轉載于:https://www.cnblogs.com/czjone/archive/2010/12/01/1893651.html
總結
以上是生活随笔為你收集整理的Sql存储过程加密和解密的全部內容,希望文章能夠幫你解決所遇到的問題。
- 上一篇: 上海欢乐谷vip免排队多少钱
- 下一篇: 疯狂的思虑