Exponentiation 冪計算 Time Limit: 500MSMemory Limit: 10000K

Total Submissions: 141868Accepted: 34673

Description
描述
Problems involving the computation of exact values of very large magnitude and precision are common.
高精度、大數(shù)值的計算問題是很常見的，

For example, the computation of the national debt is a taxing experience for many computer systems.
比如：國債的計算。

This problem requires that you write a program to compute the exact value of Rn where R is a real number ( 0.0 < R < 99.999 ) and n is an integer such that 0 < n <= 25.
現(xiàn)在要求你寫一個程序精確計算Rn，其中R是一個實數(shù)(0.0 < R < 99.999)，n是一個整數(shù)，且0 < n <= 25

Input
輸入

The input will consist of a set of pairs of values for R and n.
輸入包含多組R、n。

The R value will occupy columns 1 through 6, and the n value will be in columns 8 and 9.

R占第1到6列，n占第8到9列。

Output

輸出

The output will consist of one line for each line of input giving the exact value of R^n.
對于每組輸入，其輸出占一行，輸出值為R^n。

Leading zeros should be suppressed in the output. Insignificant trailing zeros must not be printed.
不要輸出第一位的0，末尾無意義的0也不用輸出。

Don't print the decimal point if the result is an integer.
如果結(jié)果為整數(shù)則不用輸出小數(shù)部分

Sample Input

95.123 12

0.4321 20

5.1234 15

6.7592 9

98.999 10

1.0100 12

Sample Output

548815620517731830194541.899025343415715973535967221869852721

.00000005148554641076956121994511276767154838481760200726351203835429763013462401

43992025569.928573701266488041146654993318703707511666295476720493953024

29448126.764121021618164430206909037173276672

90429072743629540498.107596019456651774561044010001

1.126825030131969720661201

Hint

提示

If you don't know how to determine wheather encounted the end of input:

如果你不知道如何判定輸入是否結(jié)束：

s is a string and n is an integer

s是字符串，n是整數(shù)。

C++

while(cin>>s>>n)

{

...

}

c

while(scanf("%s%d",s,&n)==2) //to see if the scanf read in as many items as you want

/*while(scanf(%s%d",s,&n)!=EOF) //this also work */

{

...

}

Source

East Central North America 1988

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參考：http://zhidao.baidu.com/link?url=Hw2b3JjT9lRBQx2V28ZGARQBVm4pUrPJ_tZSWvgB0qU1IOxbVYBKYWumKCbP1mnwGEzb3_LVK3iQneDftdepVa

轉(zhuǎn)載于:https://www.cnblogs.com/ikaze/p/5140083.html

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