發(fā)現(xiàn)記憶力越來越差，所以干脆搞這么一個東西，就是把C語言的最常用的語法匯編在一起，不斷完善。這樣以后只要經(jīng)常把這個回顧一下就可以了。不然去翻書太多了。。。

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f.h

#define Area 1000  
struct student{
char *last_name;
int student_id;
char grade;
int a;
};

h.c

#include <stdio.h> 
#include "f.h"
#define PI 3.1415926
#define LIMIT 20
struct employee_data
{
int a;
};int main(void)
{
//引用
printf("%d\n",Area);//字符
char c;
c='A';
int age;
char first,end;
printf("%c\n",c);
printf("%3c\n",c);
printf("%3c\n",'A');
//scanf("%d",&age);
//printf("%d\n",age);
//scanf("%c",&first);
//printf("%c\n",first);char *p1;
p1=&c;
printf("%c%d%c\n",*p1,*p1+1,*p1+2);
//printf("%c",'\a');//響鈴
//char d=getchar();//putchar()
//printf("%c\n",d);const int p_sea=20;
//p_sea=30;會報錯，向只讀變量賦值
float x,y;
x=2.0;
y=3.0;
printf("%f\n",x*y);
printf("%f\n",PI);
double d1=1.123456789;
printf("%lf\n",d1);int i=1,sum=0;
while (i<7){
sum=sum+i;
i++;
}
printf("%d\n",sum);int sz[3]={23,15,78};
sz[1]=2;
printf("%d\n",sz[1]);//求數(shù)組長度
int count=sizeof(sz)/sizeof(int);  
printf("%d\n",count);typedef int myint;
myint i1=9;
printf("%d\n",i1);
printf("%d\n",sizeof(i1));//輸出4 int是4位//指針和數(shù)組關(guān)系
int sz1[4]={40,82,67,11};
int *p;
p=sz1;
printf("*p %d\n",*p);//40
printf("*p+1 %d\n",*p+1);//41
printf("*p+2 %d\n",*p+2);//42printf("*p %d\n",*p);//40
printf("*p+1 %d\n",*(p+1));//82
printf("*p+2 %d\n",*(p+2));//67struct card{
int pips;
char suit;
}c1,c2;
c1.pips=3;
c1.suit='5';
c2=c1;
printf("struct c2.pips: %d\n",c2.pips);typedef struct{
int re;
int im;
}complex;
complex as,ac[2];
as.re=89;
ac[0].re=1;
ac[1].re=2;
printf("struct ac[0].re: %d\n",ac[0].re);
printf("struct ac[1].re: %d\n",ac[1].re);
printf("struct ac[0].re: %d\n",ac[0].re);struct student tmp;
tmp.last_name="Canada";
tmp.grade='A';
tmp.student_id=122;
tmp.a=0;
printf("struct tmp.last_name: %s\n",tmp.last_name);struct employee_data e1;
e1.a=12;
int e11=getdata(e1);
printf("struct e11: %d\n",e11);int e12=getdata_add(&e1);
printf("struct e12: %d\n",e12);//與或非
int y1=3;
int y2=0;
int y3=y1&y2;
printf("y3 &: %d\n",y3);
printf("-9 >>31: %d\n",abs(-9));#undef __FD_SETSIZE
#define __FD_SETSIZE    1024
printf("#define: %d\n",__FD_SETSIZE);return 0;
}//一個負(fù)數(shù)右移31位后會變成 0xffffffff，一個正數(shù)右移31位則為 0x00000000
//0xffffffff ^ a + a = - 1
//因為 1011 ^ 1111 = 0100 異或1111其實是把a的0和1進行了顛倒。
int abs(int x)
{return (x ^ (x >> 31)) - (x >> 31);
}int getdata(struct employee_data e)
{
return e.a;
}
int getdata_add(struct employee_data *e)
{
return e->a;
}

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