-1^22^2-3^24^2-5^2......+n^2
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-1^22^2-3^24^2-5^2......+n^2
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To simplify this expression, let's break it down into individual terms:
(-1)^2 + (2^2) + (-3)^2 + (4^2) + (-5)^2 + ... + (n^2)
The first term is (-1)^2 which equals 1.
The second term is (2^2) which equals 4.
The third term is (-3)^2 which equals 9.
The fourth term is (4^2) which equals 16.
In general, the nth term is (n^2).
So, the simplified expression is:
1 + 4 + 9 + 16 + ... + (n^2)
This is an arithmetic series with a common difference of 5, as each term is obtained by adding 5 to the previous term.
To find the sum of an arithmetic series, you can use the formula:
S = (n/2) * (first term + last term)
In this case, the first term is 1 and the last term is n^2.
So, the simplified expression becomes:
S = (n/2) * (1 + n^2)
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