取表的前10條記錄
with a as(select *,row_number()over(order by department)rn from _SucceedStaff )

select * from a where rn<=10

取表的任意中間幾行的記錄eg：10-30
with a as(select *,row_number()over(order by department)rn from _SucceedStaff )
select * from a where rn>=10 and rm<=30

附：常用幾種數據庫，取前10條記錄的sql語句寫法
http://blog.csdn.net/lzz313/archive/2006/12/19/1449572.aspx

access：
select top (10) * from table1 where 1=1

db2：
select column from table where 1=1 fetch first 10 rows only

mysql：
select * from table1 where 1=1 limit 10

sql server:
讀取前10條：select top (10) * from table1 where 1=1
讀取后10條：select top (10) * from table1 order by id desc

oracle：
select * from table1 where rownum<=10

取每日日期的前十條記錄

SQL表列如下：

單號 日期
1 2011-09-10
2 2011-09-10

select?*?from?tb?a?where?單號?in(select?top?10?單號?from?tb?where?日期=a.日期?order?by?單號) select * from ( select *,rank () over(partition by day(日期) order by 日期) rk from tb ) t where t.rk<=10 select * from(select *,row_number()over(order by name)rn from _SucceedStaff )t where t.rn<=10（對比上面）

總結

以上是生活随笔為你收集整理的sql 取表的前10条记录，任意中间几行的记录的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。