树状数组求逆序数
解題關鍵:離散化。
#include<cstdio> #include<cstring> #include<algorithm> #include<cstdlib> #include<iostream> #include<cmath> #define maxn 500004 using namespace std; typedef long long ll; struct node{int id,val; }a[maxn]; int bits[maxn],p[maxn]; bool cmp(const node &a,const node &b){return a.val<b.val; } int n; void add(int i,int x){while(i<=maxn){bits[i]+=x;i+=i&-i;} }int sum(int i){int s=0;while(i>0){s+=bits[i];i-=i&-i;}return s; }int main(){while(scanf("%d",&n)&&n){for(int i=1;i<=n;i++) scanf("%d",&a[i].val),a[i].id=i;sort(a+1,a+n+1,cmp);for(int i=1;i<=n;i++) p[a[i].id]=i;ll ans=0;memset(bits,0,sizeof bits);for(int i=1;i<=n;i++){add(p[i],1);ans+=i-sum(p[i]);}printf("%lld\n",ans);} }?
轉載于:https://www.cnblogs.com/elpsycongroo/p/9038357.html
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