简单的麻将胡牌算法
? ? ? ? ? 今天嘗試寫了一個簡單麻將的胡牌算法,規(guī)則很簡單,看代碼:
#include<stdio.h> #include<string.h>/*1,2,3,4,5,6,7,8,9 萬11,12,13,14,15,16,17,18,19 索21,22,23,24,25,26,27,28,29 餅 *///胡牌規(guī)則:要一對將,其他的是順子或是叉牌,這是比較簡單的胡牌規(guī)則int check_shunzi(int a,int b,int c) {//printf("shunzi= %d,%d,%d\n",a,b,c);if(a - b == 1){if(b - c == 1)return 1;}else if (b - a == 1){if (c - b == 1)return 1;}else{return 0;}return 0; }int check_chapai(int a,int b,int c) {//printf("chapai= %d,%d,%d\n",a,b,c);if(a == b)if((b == c))return 1;elsereturn 0; }int main() {//麻將摸到首先要進行排序,假設(shè)下面是排序后的結(jié)果,排序后同,萬,餅分別在一起int pooker[] = {3,3,4,4,4,11,12,13,14,14,14,22,22,22};int dui_count = 0;int i = 0;for(i = 0;i < 12;i++){if(pooker[i] == pooker[i + 1]){if(check_chapai(pooker[i],pooker[i + 1],pooker[i + 2])){i += 2;}else{i += 1;dui_count++;}}else if(check_shunzi(pooker[i],pooker[i + 1],pooker[i + 2])){i += 2;}else{printf("不能胡牌\n");return 0;}}if(dui_count == 1){printf("可以胡牌\n");}else{printf("不能胡牌\n");}return 0; }也就是根據(jù)相應(yīng)的麻將規(guī)則去寫邏輯。
總結(jié)
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