用JSON或者XML等，不存在此問題，或者說相對容易解決此問題。

以下是指特定用Soap來進行序列化和反序列化中碰到的。

在一個程序集中：

class Program
{
??? static void Main(string[] args)
??? {
??????? //Serialize();
??????? A a = new A();
??????? string re = Tool.Serialize(a);
??????? Console.WriteLine(re);
??????? var b = Tool.Desrialize<A>(re);
??????? Console.WriteLine(b.ToString());
??? }
}

class Tool
{
??? public static string Serialize<T>(T obj)
??? {
??????? try
??????? {
??????????? IFormatter formatter = new BinaryFormatter();
??????????? MemoryStream stream = new MemoryStream();
??????????? formatter.Serialize(stream, obj);
??????????? stream.Position = 0;
??????????? byte[] buffer = new byte[stream.Length];
??????????? stream.Read(buffer, 0, buffer.Length);
??????????? stream.Flush();
??????????? stream.Close();
??????????? //return Convert.ToBase64String(buffer);
??????????? string utf8String = Encoding.ASCII.GetString(buffer);
??????????? return utf8String;
??????? }
??????? catch (Exception ex)
??????? {
??????????? throw new Exception("fail:" + ex.Message);
??????? }
??? }

??? public static T Desrialize<T>(string str) where T : class
??? {
??????? T obj = null;

??????? try
??????? {
??????????? IFormatter formatter = new BinaryFormatter();
??????????? byte[] buffer = Encoding.ASCII.GetBytes(str);
??????????? //byte[] buffer = Convert.FromBase64String(str);
??????????? MemoryStream stream = new MemoryStream(buffer);
??????????? obj = (T)formatter.Deserialize(stream);
??????????? stream.Flush();
??????????? stream.Close();
??????? }
??????? catch (Exception ex)
??????? {
??????????? throw new Exception("fail:" + ex.Message);
??????? }
??????? return obj;
??? }
}

[Serializable]
public class A
{
??? public string a;
}

?

在另一個程序集中：

class Program
{
??? static void Main(string[] args)
??? {
??????? string x = "AAEAAAD/AQAAAAAAAAAMAgAAAEpDb25zb2xlQXBwbGljYXRpb24zLCBWZXJzaW9uPTEuMC4wLjAsIEN1bHR1cmU9bmV1dHJhbCwgUHVibGljS2V5VG9rZW49bnVsbAUBAAAAFUNvbnNvbGVBcHBsaWNhdGlvbjMuQQEAAAABYQECAAAACgs=";

??????? var s = Tool.Desrialize<A>(x);
??????? Console.WriteLine(s.ToString());
??? }
}

class Tool
{
??? public static string Serialize<T>(T obj)
??? {
??????? try
??????? {
??????????? IFormatter formatter = new BinaryFormatter();
??????????? MemoryStream stream = new MemoryStream();
??????????? formatter.Serialize(stream, obj);
??????????? stream.Position = 0;
??????????? byte[] buffer = new byte[stream.Length];
??????????? stream.Read(buffer, 0, buffer.Length);
??????????? stream.Flush();
??????????? stream.Close();
??????????? return Convert.ToBase64String(buffer);
??????? }
??????? catch (Exception ex)
??????? {
??????????? throw new Exception("fail:" + ex.Message);
??????? }
??? }

??? public static T Desrialize<T>(string str) where T : class
??? {
??????? T obj = null;
??????? try
??????? {
??????????? IFormatter formatter = new BinaryFormatter();
??????????? byte[] buffer = Convert.FromBase64String(str);
??????????? MemoryStream stream = new MemoryStream(buffer);
??????????? obj = (T)formatter.Deserialize(stream);
??????????? stream.Flush();
??????????? stream.Close();
??????? }
??????? catch (Exception ex)
??????? {
??????????? throw new Exception("fail:" + ex.Message);
??????? }
??????? return obj;
??? }
}

[Serializable]
public class A
{
??? public string a;
}

?

無非就是替換其中關于類型程序集信息的替換。

當然，此解決方案的一個問題是，隨著每次程序集版本號的修改，代碼中的 Replace 部分也要做修改。蛋疼。

轉載于:https://www.cnblogs.com/luminji/p/4316443.html

總結

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