題目：

依照一個存著新進貨物的二維數組，更新存著現有庫存(在 arr1 中)的二維數組. 如果貨物已存在則更新數量 . 如果沒有對應貨物則把其加入到數組中，更新最新的數量. 返回當前的庫存數組，且按貨物名稱的字母順序排列.

示例：

updateInventory([[21, "Bowling Ball"], [2, "Dirty Sock"], [1, "Hair Pin"], [5, "Microphone"]], [[2, "Hair Pin"], [3, "Half-Eaten Apple"], [67, "Bowling Ball"], [7, "Toothpaste"]]).length 應該返回一個長度為6的數組.
updateInventory([[21, "Bowling Ball"], [2, "Dirty Sock"], [1, "Hair Pin"], [5, "Microphone"]], [[2, "Hair Pin"], [3, "Half-Eaten Apple"], [67, "Bowling Ball"], [7, "Toothpaste"]]) 應該返回 [[88, "Bowling Ball"], [2, "Dirty Sock"], [3, "Hair Pin"], [3, "Half-Eaten Apple"], [5, "Microphone"], [7, "Toothpaste"]].
updateInventory([[21, "Bowling Ball"], [2, "Dirty Sock"], [1, "Hair Pin"], [5, "Microphone"]], []) 應該返回 [[21, "Bowling Ball"], [2, "Dirty Sock"], [1, "Hair Pin"], [5, "Microphone"]].
updateInventory([], [[2, "Hair Pin"], [3, "Half-Eaten Apple"], [67, "Bowling Ball"], [7, "Toothpaste"]]) 應該返回 [[67, "Bowling Ball"], [2, "Hair Pin"], [3, "Half-Eaten Apple"], [7, "Toothpaste"]].
updateInventory([[0, "Bowling Ball"], [0, "Dirty Sock"], [0, "Hair Pin"], [0, "Microphone"]], [[1, "Hair Pin"], [1, "Half-Eaten Apple"], [1, "Bowling Ball"], [1, "Toothpaste"]]) 應該返回 [[1, "Bowling Ball"], [0, "Dirty Sock"], [1, "Hair Pin"], [1, "Half-Eaten Apple"], [0, "Microphone"], [1, "Toothpaste"]].

分析思路:

遍歷進貨數組，取每一個元素，然后遍歷庫存數組，若進貨的名稱已存在，直接修改數目，若進貨的名稱不存在，這 push 到庫存中；
從測試用例中可知：最終的庫存列表需要根據名稱進行排序，從字符的低到高進行排序；

代碼：

<script type="text/javascript">
	function updateInventory(arr1, arr2) {
		// All inventory must be accounted for or you're fired!
		for (var i = 0; i < arr2.length; i++) {
			for (var j = 0; j < arr1.length; j++) {
				if (arr1[j][1] === arr2[i][1]) {
					arr1[j][0] += arr2[i][0];
					break;
				}
			}

			if (j == arr1.length) {
				arr1.push(arr2[i]);
			}
		}

		return arr1.sort(function(a, b) {
			return a[1].charCodeAt(0) - b[1].charCodeAt(0);
		});

	}
</script>

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