??? 兩個十進制數，反向存儲在單向鏈表里，每位數占一個節點。求和的鏈表。

/** * Definition for singly-linked list. * struct ListNode { * int val; * ListNode *next; * ListNode(int x) : val(x), next(NULL) {} * }; */ ? int add(int a, int b, int &carry) { int c = a + b + carry; carry = c / 10; return c % 10; } ? ListNode *add_two_numbers(ListNode *l1, ListNode *l2) { ListNode *head = NULL, *rear = NULL; if (l1 == NULL) return l2; if (l2 == NULL) return l1; int carry = 0; while (l1 != NULL || l2 != NULL) { int val = 0; if (l1 == NULL) { val = add(0, l2->val, carry); l2 = l2->next; } else if (l2 == NULL) { val = add(l1->val, 0, carry); l1 = l1->next; } else { val = add(l1->val, l2->val, carry); l1 = l1->next; l2 = l2->next; } ListNode *new_node = new ListNode(val); if (head == NULL) head = new_node; if (rear == NULL) { rear = new_node; } else { rear->next = new_node; rear = rear->next; } } if (carry != 0 && rear != NULL) { rear->next = new ListNode(carry); } return head; }

總結

以上是生活随笔為你收集整理的Add Two Numbers的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。