這比你想象的要容易得多.假設(shè)您有三次,t1,t2和tn分別代表from,to和user time.將這些時間視為六位數(shù)字(從000000到235959)并檢查：

>如果t1和t2出現(xiàn)在午夜邊界的同一側(cè)

>檢查tn是否位于t1和t2之間

>其他

>檢查tn和t1之間是否存在tn

代碼和測試：

function check_time($t1, $t2, $tn) {

$t1 = +str_replace(":", "", $t1);

$t2 = +str_replace(":", "", $t2);

$tn = +str_replace(":", "", $tn);

if ($t2 >= $t1) {

return $t1 <= $tn && $tn < $t2;

} else {

return ! ($t2 <= $tn && $tn < $t1);

}

}

$tests = array(

array("16:00:00", "22:30:00", "15:00:00"),

array("16:00:00", "22:30:00", "16:00:00"),

array("16:00:00", "22:30:00", "22:29:59"),

array("16:00:00", "22:30:00", "22:30:00"),

array("16:00:00", "22:30:00", "23:59:59"),

array("22:30:00", "16:00:00", "22:29:59"),

array("22:30:00", "16:00:00", "22:30:00"),

array("22:30:00", "16:00:00", "15:59:59"),

array("22:30:00", "16:00:00", "16:00:00"),

array("22:30:00", "16:00:00", "17:00:00")

);

foreach($tests as $test) {

list($t1, $t2, $t0) = $test;

echo "$t1 - $t2 contains $t0: " . (check_time($t1, $t2, $t0) ? "yes" : "no") . "\n";

}

// OUTPUT

//

// 16:00:00 - 22:30:00 contains 15:00:00: no

// 16:00:00 - 22:30:00 contains 16:00:00: yes

// 16:00:00 - 22:30:00 contains 22:29:59: yes

// 16:00:00 - 22:30:00 contains 22:30:00: no

// 16:00:00 - 22:30:00 contains 23:59:59: no

// 22:30:00 - 16:00:00 contains 22:29:59: no

// 22:30:00 - 16:00:00 contains 22:30:00: yes

// 22:30:00 - 16:00:00 contains 15:59:59: yes

// 22:30:00 - 16:00:00 contains 16:00:00: no

// 22:30:00 - 16:00:00 contains 17:00:00: no

總結(jié)

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