有关于Java Map,应该掌握的8个问题
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最近幾天看了幾篇有關于Java Map的外國博文,寫得非常不錯,所以整理了Java map 應該掌握的8個問題,都是日常開發司空見慣的問題,希望對大家有幫助;如果有不正確的地方,歡迎提出,萬分感謝哈~
本章節所有代碼demo已上傳github
1、如何把一個Map轉化為List
日常開發中,我們經常遇到這種場景,把一個Map轉化為List。map轉List有以下三種轉化方式:
把map的鍵key轉化為list
把map的值value轉化為list
把map的鍵值key-value轉化為list
偽代碼如下:
// key list List keyList = new ArrayList(map.keySet()); // value list List valueList = new ArrayList(map.values()); // key-value list List entryList = new ArrayList(map.entrySet());示例代碼:
public class Test {public static void main(String[] args) {Map<Integer, String> map = new HashMap<>();map.put(2, "jay");map.put(1, "whx");map.put(3, "huaxiao");//把一個map的鍵轉化為listList<Integer> keyList = new ArrayList<>(map.keySet());System.out.println(keyList);//把map的值轉化為listList<String> valueList = new ArrayList<>(map.values());System.out.println(valueList);把map的鍵值轉化為listList entryList = new ArrayList(map.entrySet());System.out.println(entryList);} }運行結果:
[1, 2, 3] [whx, jay, huaxiao] [1=whx, 2=jay, 3=huaxiao]2、如何遍歷一個Map
我們經常需要遍歷一個map,可以有以下兩種方式實現:
通過entrySet+for實現遍歷
for(Entry entry: map.entrySet()) {// get keyK key = entry.getKey();// get valueV value = entry.getValue(); }實例代碼:
public class EntryMapTest {public static void main(String[] args) {Map<Integer, String> map = new HashMap<>();map.put(2, "jay");map.put(1, "whx");map.put(3, "huaxiao");for(Map.Entry entry: map.entrySet()) {// get keyInteger key = (Integer) entry.getKey();// get valueString value = (String) entry.getValue();System.out.println("key:"+key+",value:"+value);}} }通過Iterator+while實現遍歷
Iterator itr = map.entrySet().iterator(); while(itr.hasNext()) {Entry entry = itr.next();// get keyK key = entry.getKey();// get valueV value = entry.getValue(); }實例代碼:
public class IteratorMapTest {public static void main(String[] args) {Map<Integer, String> map = new HashMap<>();map.put(2, "jay");map.put(1, "whx");map.put(3, "huaxiao");Iterator itr = map.entrySet().iterator();while(itr.hasNext()) {Map.Entry entry = (Map.Entry) itr.next();// get keyInteger key = (Integer) entry.getKey();// get valueString value = (String) entry.getValue();System.out.println("key:"+key+",value:"+value);}} }運行結果:
key:1,value:whx key:2,value:jay key:3,value:huaxiao3、如何根據Map的keys進行排序
對Map的keys進行排序,在日常開發很常見,主要有以下兩種方式實現。
把Map.Entry放進list,再用Comparator對list進行排序
List list = new ArrayList(map.entrySet()); Collections.sort(list, (Entry e1, Entry e2)-> {return e1.getKey().compareTo(e2.getKey()); });實例代碼:
public class SortKeysMapTest {public static void main(String[] args) {Map<String, String> map = new HashMap<>();map.put("2010", "jay");map.put("1999", "whx");map.put("3010", "huaxiao");List<Map.Entry<String,String>> list = new ArrayList<>(map.entrySet());Collections.sort(list, (Map.Entry e1, Map.Entry e2)-> {return e1.getKey().toString().compareTo(e2.getKey().toString());});for (Map.Entry entry : list) {System.out.println("key:" + entry.getKey() + ",value:" + entry.getValue());}} }使用SortedMap+TreeMap+Comparator實現
SortedMap sortedMap = new TreeMap(new Comparator() {@Overridepublic int compare(K k1, K k2) {return k1.compareTo(k2);} }); sortedMap.putAll(map);實例代碼:
public class SortKeys2MapTest {public static void main(String[] args) {Map<String, String> map = new HashMap<>();map.put("2010", "jay");map.put("1999", "whx");map.put("3010", "huaxiao");SortedMap sortedMap = new TreeMap(new Comparator<String>() {@Overridepublic int compare(String k1, String k2) {return k1.compareTo(k2);}});sortedMap.putAll(map);Iterator itr = sortedMap.entrySet().iterator();while(itr.hasNext()) {Map.Entry entry = (Map.Entry) itr.next();// get keyString key = (String) entry.getKey();// get valueString value = (String) entry.getValue();System.out.println("key:"+key+",value:"+value);}} }運行結果:
key:1999,value:whx key:2010,value:jay key:3010,value:huaxiao4、如何對Map的values進行排序
List list = new ArrayList(map.entrySet()); Collections.sort(list, (Entry e1, Entry e2) ->{return e1.getValue().compareTo(e2.getValue());});實例代碼:
public class SortValuesMapTest {public static void main(String[] args) {Map<String, String> map = new HashMap<>();map.put("2010", "jay");map.put("1999", "whx");map.put("3010", "huaxiao");List <Map.Entry<String,String>>list = new ArrayList<>(map.entrySet());Collections.sort(list, (Map.Entry e1, Map.Entry e2)-> {return e1.getValue().toString().compareTo(e2.getValue().toString());});for (Map.Entry entry : list) {System.out.println("key:" + entry.getKey() + ",value:" + entry.getValue());}} }運行結果:
key:3010,value:huaxiao key:2010,value:jay key:1999,value:whx5、如何初始化一個靜態/不可變的Map
初始化一個靜態不可變的map,單單static final+static代碼塊還是不行的,如下:
public class Test1 {private static final Map <Integer,String>map;static {map = new HashMap<Integer, String>();map.put(1, "one");map.put(2, "two");}public static void main(String[] args) {map.put(3, "three");Iterator itr = map.entrySet().iterator();while(itr.hasNext()) {Map.Entry entry = (Map.Entry) itr.next();// get keyInteger key = (Integer) entry.getKey();// get valueString value = (String) entry.getValue();System.out.println("key:"+key+",value:"+value);}} }這里面,map繼續添加元素(3,"three"),發現是OK的,運行結果如下:
key:1,value:one key:2,value:two key:3,value:three真正實現一個靜態不可變的map,需要Collections.unmodifiableMap,代碼如下:
public class Test2 {private static final Map<Integer, String> map;static {Map<Integer,String> aMap = new HashMap<>();aMap.put(1, "one");aMap.put(2, "two");map = Collections.unmodifiableMap(aMap);}public static void main(String[] args) {map.put(3, "3");Iterator itr = map.entrySet().iterator();while(itr.hasNext()) {Map.Entry entry = (Map.Entry) itr.next();// get keyInteger key = (Integer) entry.getKey();// get valueString value = (String) entry.getValue();System.out.println("key:"+key+",value:"+value);}} }運行結果如下:
可以發現,繼續往map添加元素是會報錯的,實現真正不可變的map。
6、HashMap, TreeMap, and Hashtable,ConcurrentHashMap的區別
| 有序性 | 否 | 是 | 否 | 否 |
| null k-v | 是-是 | 否-是 | 否-否 | 否-否 |
| 線性安全 | 否 | 否 | 是 | 是 |
| 時間復雜度 | O(1) | O(log n) | O(1) | O(log n) |
| 底層結構 | 數組+鏈表 | 紅黑樹 | 數組+鏈表 | 紅黑樹 |
7、如何創建一個空map
如果map是不可變的,可以這樣創建:
Map map=Collections.emptyMap(); or Map<String,String> map=Collections.<String, String>emptyMap(); //map1.put("1", "1"); 運行出錯如果你希望你的空map可以添加元素的,可以這樣創建
Map map = new HashMap();8、有關于map的復制
有關于hashmap的復制,在日常開發中,使用也比較多。主要有 =,clone,putAll,但是他們都是淺復制,使用的時候注意啦,可以看一下以下例子:
例子一,使用=復制一個map:
public class CopyMapAssignTest {public static void main(String[] args) {Map<Integer, User> userMap = new HashMap<>();userMap.put(1, new User("jay", 26));userMap.put(2, new User("fany", 25));//Shallow cloneMap<Integer, User> clonedMap = userMap;//Same as userMapSystem.out.println(clonedMap);System.out.println("\nChanges reflect in both maps \n");//Change a value is clonedMapclonedMap.get(1).setName("test");//Verify content of both mapsSystem.out.println(userMap);System.out.println(clonedMap);} }運行結果:
{1=User{name='jay', age=26}, 2=User{name='fany', age=25}} Changes reflect in both maps {1=User{name='test', age=26}, 2=User{name='fany', age=25}} {1=User{name='test', age=26}, 2=User{name='fany', age=25}}從運行結果看出,對cloneMap修改,兩個map都改變了,所以=是淺復制。
例子二,使用hashmap的clone復制:
public class CopyCloneMapTest {public static void main(String[] args) {HashMap<Integer, User> userMap = new HashMap<>();userMap.put(1, new User("jay", 26));userMap.put(2, new User("fany", 25));//Shallow cloneHashMap<Integer, User> clonedMap = (HashMap<Integer, User>) userMap.clone();//Same as userMapSystem.out.println(clonedMap);System.out.println("\nChanges reflect in both maps \n");//Change a value is clonedMapclonedMap.get(1).setName("test");//Verify content of both mapsSystem.out.println(userMap);System.out.println(clonedMap);} }運行結果:
{1=User{name='jay', age=26}, 2=User{name='fany', age=25}} Changes reflect in both maps {1=User{name='test', age=26}, 2=User{name='fany', age=25}} {1=User{name='test', age=26}, 2=User{name='fany', age=25}}從運行結果看出,對cloneMap修改,兩個map都改變了,所以hashmap的clone也是淺復制。
例子三,通過putAll操作
public class CopyPutAllMapTest {public static void main(String[] args) {HashMap<Integer, User> userMap = new HashMap<>();userMap.put(1, new User("jay", 26));userMap.put(2, new User("fany", 25));//Shallow cloneHashMap<Integer, User> clonedMap = new HashMap<>();clonedMap.putAll(userMap);//Same as userMapSystem.out.println(clonedMap);System.out.println("\nChanges reflect in both maps \n");//Change a value is clonedMapclonedMap.get(1).setName("test");//Verify content of both mapsSystem.out.println(userMap);System.out.println(clonedMap);} }運行結果:
{1=User{name='jay', age=26}, 2=User{name='fany', age=25}} Changes reflect in both maps {1=User{name='test', age=26}, 2=User{name='fany', age=25}} {1=User{name='test', age=26}, 2=User{name='fany', age=25}}從運行結果看出,對cloneMap修改,兩個map都改變了,所以putAll還是淺復制。
那么,如何實現深度復制呢?
可以使用序列化實現,如下為谷歌Gson序列化HashMap,實現深度復制的例子:
public class CopyDeepMapTest {public static void main(String[] args) {HashMap<Integer, User> userMap = new HashMap<>();userMap.put(1, new User("jay", 26));userMap.put(2, new User("fany", 25));//Shallow cloneGson gson = new Gson();String jsonString = gson.toJson(userMap);Type type = new TypeToken<HashMap<Integer, User>>(){}.getType();HashMap<Integer, User> clonedMap = gson.fromJson(jsonString, type);//Same as userMapSystem.out.println(clonedMap);System.out.println("\nChanges reflect in only one map \n");//Change a value is clonedMapclonedMap.get(1).setName("test");//Verify content of both mapsSystem.out.println(userMap);System.out.println(clonedMap);} }運行結果:
{1=User{name='jay', age=26}, 2=User{name='fany', age=25}} Changes reflect in only one map {1=User{name='jay', age=26}, 2=User{name='fany', age=25}} {1=User{name='test', age=26}, 2=User{name='fany', age=25}}從運行結果看出,對cloneMap修改,userMap沒有被改變,所以是深度復制。
參考與感謝
Top 9 questions about Java Maps
Best way to create an empty map in Java
How to clone HashMap – Shallow and Deep Copy
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