例如我們需要將一下數據的第二列從and處拆分為兩列：

before = data.frame(attr = c(1,30,4,6), type=c('foo_and_bar','foo_and_bar_2'))

attr type 1 1 foo_and_bar 2 30 foo_and_bar_2 3 4 foo_and_bar 4 6 foo_and_bar_2

==>

attr type_1 type_2 1 1 foo bar 2 30 foo bar_2 3 4 foo bar 4 6 foo bar_2

使用stringr包的str_split_fixed函數

library(stringr) str_split_fixed(before$type, "_and_", 2)

使用do.call函數 （do.call(what, args, quote = FALSE, envir = parent.frame())）

before <- data.frame(attr = c(1,30,4,6), type=c('foo_and_bar','foo_and_bar_2')) out <- strsplit(as.character(before$type),'_and_') do.call(rbind, out)

使用tidyr包

library(dplyr) library(tidyr) before <- data.frame(attr = c(1, 30 ,4 ,6 ), type = c('foo_and_bar', 'foo_and_bar_2')) before %>% separate(type, c("foo", "bar"), "_and_")

使用sapply 以及 "["

before$type_1 < sapply(strsplit(as.character(before$type),'_and_'), "[", 1) before$type_2 < sapply(strsplit(as.character(before$type),'_and_'), "[", 2)

或者

before <- data.frame(attr = c(1,30,4,6), type=c('foo_and_bar','foo_and_bar_2')) after <- with(before, data.frame(attr = attr)) after <- cbind(after, data.frame(t(sapply(out, `[`)))) names(after)[2:3] <- paste("type", 1:2, sep = "_")

使用unlist后重新劃分矩陣

before <- data.frame(attr = c(1,30,4,6), type=c('foo_and_bar','foo_and_bar_2')) tmp <- matrix(unlist(strsplit(as.character(before$type), '_and_')), ncol=2,byrow=TRUE) #you should show how many columns you would get after spliting after <- cbind(before$attr, as.data.frame(tmp)) names(after) <- c("attr", "type_1", "type_2")

轉載于:https://www.cnblogs.com/arkenstone/p/5444453.html

總結

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