oracle 去除英文字母,请教:如何去掉字段中的所有标点符号(包括全角的和半角的)...
TRANSLATE
Syntax
參見(jiàn)附圖
Purpose
TRANSLATE returns char with all occurrences of each character in from replaced by
its corresponding character in to. Characters in char that are not in from are not
replaced. The argument from can contain more characters than to. In this case, the
extra characters at the end of from have no corresponding characters in to. If these
extra characters appear in char, they are removed from the return value. You cannot
use an empty string for to to remove all characters in from from the return value.
Oracle interprets the empty string as null, and if this function has a null argument,
it returns null.
Example 1
The following statement translates a license number. All letters ’ABC...Z’ are
translated to ’X’ and all digits ’012 . . . 9’ are translated to ’9’:
SELECT TRANSLATE(’2KRW229’,
’0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ’,
’9999999999XXXXXXXXXXXXXXXXXXXXXXXXXX’) "License"
FROM DUAL;
License
--------
9XXX999
Example 2
The following statement returns a license number with the characters removed and
the digits remaining:
SELECT TRANSLATE(’2KRW229’,
’0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ’, ’0123456789’)
"Translate example"
FROM DUAL;
Translate example
-----------------
2229
del.jpg
(10.31 KB, 下載次數(shù): 49)
2005-10-14 13:15 上傳
總結(jié)
以上是生活随笔為你收集整理的oracle 去除英文字母,请教:如何去掉字段中的所有标点符号(包括全角的和半角的)...的全部?jī)?nèi)容,希望文章能夠幫你解決所遇到的問(wèn)題。
- 上一篇: ustc小道消息20211215
- 下一篇: Linux iNode 双网卡,已解决: