1050?String Subtraction?（20?分)

Given two strings?S?1???and?S?2??,?S=S?1???S?2???is defined to be the remaining string after taking all the characters in?S?2???from?S?1??. Your task is simply to calculate?S?1???S?2???for any given strings. However, it might not be that simple to do it?fast.

Input Specification:

Each input file contains one test case. Each case consists of two lines which gives?S?1???and?S?2??, respectively. The string lengths of both strings are no more than?10?4??. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

Output Specification:

For each test case, print?S?1???S?2???in one line.

Sample Input:

They are students. aeiou

Sample Output:

Thy r stdnts. #include<set> #include<map> #include<list> #include<queue> #include<deque> #include<cmath> #include<stack> #include<cstdio> #include<string> #include<bitset> #include<vector> #include<cstring> #include<cstdlib> #include<iostream> #include<algorithm> #include<bits/stdc++.h> using namespace std;#define e exp(1) #define pp acos(-1) #define mod 1000000007 #define inf 0x3f3f3f3f #define ll long long #define ull unsigned long long #define mem(a,b) memset(a,b,sizeof(a)) int gcd(int a,int b) {return b?gcd(b,a%b):a; }const int maxn=505; int a[maxn]; int main() {string s1,s2;getline(cin,s1);getline(cin,s2);for(int i=0; i<s2.size(); i++){a[s2[i]]++;}for(int i=0; i<s1.size(); i++){if(a[s1[i]])continue;else cout<<s1[i];}puts("");return 0; }

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