javafor循環打印圖案

Input a number and print the following box pattern in C language,

輸入數字并以C語言打印以下框形 ，

4 4 4 4 4 4 44 3 3 3 3 3 4 4 3 2 2 2 3 4 4 3 2 1 2 3 4 4 3 2 2 2 3 4 4 3 3 3 3 3 4 4 4 4 4 4 4 4

Input format:

輸入格式：

The input will contain a single integer.

輸入將包含一個整數。

Constraints:

限制條件：

1<=n<=100

1 <= n <= 100

Output format:

輸出格式：

Print the pattern mentioned in the problem statement.

打印問題陳述中提到的模式。

Example

例

Input:2Output:2 2 2 2 1 2 2 2 2

代碼以C語言打印盒子圖案 (Code to print the box pattern in C)

//Code to print the box pattern in C #include <stdio.h>int main() {int n, i, j, t; //n is representing number of the output box//input nprintf("Enter the value of n: ");scanf("%d", &n);t = 2 * n - 1;i = t; //i and j are the number of rows and columns of the box.j = t;// Declare box as a 2-D matrix having i number of rows //and j number of columnsint a[i][j], k, m, p;p = n;m = 0;for (k = 0; k < p; k++) {for (i = m; i < t; i++) {for (j = m; j < t; j++) {if (i == m || i == (t - 1) || j == m || j == (t - 1)) {a[i][j] = n;if (n == 1) {break;}}}}t = t - 1;n = n - 1;m = m + 1;}t = 2 * m - 1;for (i = 0; i < t; i++) {for (j = 0; j < t; j++) {printf("%d ", a[i][j]);}printf("\n");}return 0; }

Output

輸出量

First run: Enter the value of n: 2 2 2 2 2 1 2 2 2 2Second run: Enter the value of n: 4 4 4 4 4 4 4 4 4 3 3 3 3 3 4 4 3 2 2 2 3 4 4 3 2 1 2 3 4 4 3 2 2 2 3 4 4 3 3 3 3 3 4 4 4 4 4 4 4 4

翻譯自: https://www.includehelp.com/c-programs/print-box-pattern-using-loops.aspx

javafor循環打印圖案

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