Python | 程序从列表中删除重复的元素
Example:
例:
Input:list1: [10, 20, 10, 20, 30, 40, 30, 50]Output:List after removing duplicate elementslist2: [10, 20, 30, 40, 50]Logic:
邏輯:
To implement the program is too easy, we have to append elements one by one to another list by checking whether element is available in the new list or not.
要實現該程序太容易了,我們必須通過檢查元素在新列表中是否可用,將元素逐個追加到另一個列表。
Let suppose, 20 is available three times in the list list1 and when we append 20 (first occurrence) to the list list2, it will be appended, but when we append 20 (second occurrence) to the list list2, condition will be false and item will not be appended. And finally, we will get list without duplicate elements.
假設,20在列表list1中有3次可用,并且當我們將20(第一次出現)附加到列表list2時 ,它將被附加,但是當我們將20(第二次出現)附加到列表list2時 ,條件將為false并且項目將不會被追加。 最后,我們將獲得沒有重復元素的列表。
Program:
程序:
# declare list list1 = [10, 20, 10, 20, 30, 40, 30, 50]# creating another list with unique elements # declare another list list2 = []# appending elements for n in list1:if n not in list2:list2.append(n)# printing the lists print "Original list" print "list1: ", list1 print "List after removing duplicate elements" print "list2: ", list2Output
輸出量
Original listlist1: [10, 20, 10, 20, 30, 40, 30, 50]List after removing duplicate elementslist2: [10, 20, 30, 40, 50]Program (Defining User defines function):
程序(定義用戶定義功能):
# Function to remove duplicates def removeDuplicates (list1):# declare another listlist2 = []# appending elements for n in list1:if n not in list2:list2.append (n)return list2# Main code # declare a list list1 = [10, 20, 10, 20, 30, 40, 30, 50] # print the list print "Original list: ", list1 print "List after duplicate remove: ", removeDuplicates (list1)Output
輸出量
Original list: [10, 20, 10, 20, 30, 40, 30, 50]List after duplicate remove: [10, 20, 30, 40, 50]翻譯自: https://www.includehelp.com/python/remove-duplicate-elements-from-the-list.aspx
總結
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