我試圖解決這樣一個問題：我將字符串作為輸入，然后刪除偶數計數的重復字符。在

在輸入：AZXXZYYYDDDYZZZ在

輸出：azzz

你能幫我做這個嗎。在

我的嘗試在刪除重復字符方面效果不錯，但我一直致力于如何刪除偶數個重復字符# Utility function to convert string to list

def toMutable(string):

temp = []

for x in string:

temp.append(x)

return temp

# Utility function to convert string to list

def toString(List):

return ''.join(List)

# Function to remove duplicates in a sorted array

def removeDupsSorted(List):

res_ind = 1

ip_ind = 1

# In place removal of duplicate characters

while ip_ind != len(List):

if List[ip_ind] != List[ip_ind-1]:

List[res_ind] = List[ip_ind]

res_ind += 1

ip_ind+=1

# After above step string is efgkorskkorss.

# Removing extra kkorss after string

string = toString(List[0:res_ind])

return string

# Function removes duplicate characters from the string

# This function work in-place and fills null characters

# in the extra space left

def removeDups(string):

# Convert string to list

List = toMutable(string)

# Sort the character list

List.sort()

# Remove duplicates from sorted

return removeDupsSorted(List)

# Driver program to test the above functions

string = "geeksforgeeks"

print removeDups(string)

總結

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