Subsequences (easy version)
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Subsequences (easy version)
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https://codeforces.com/contest/1183/problem/E
題解:樸素
/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int #define endl "\n" using namespace std; typedef long long ll; //typedef __int128 lll; const int N=100000+10; const int M=100000+10; const int MOD=1e9+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,p,l,r,u,v; int ans,cnt,flag,temp,sum; char s[N]; struct node{}; int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endif//ios::sync_with_stdio(false);//cin.tie(0);//cout.tie(0);//scanf("%d",&t);//while(t--){scanf("%d%d",&n,&k);scanf("%s",s);int sol = 0;set<string> st;queue<string> q;q.push(s);st.insert(s);while(!q.empty() && st.size() < k) {string newS = q.front();q.pop();for(int i = 0; i < newS.length(); i++) {string ns = newS;ns.erase(i, 1);if(!st.count(ns) && st.size() < k) {st.insert(ns);q.push(ns);sol += n - ns.length();}}}cout<<(st.size() < k?-1:sol)<<endl;//}#ifdef DEBUGprintf("Time cost : %lf s\n",(double)clock()/CLOCKS_PER_SEC); #endif//cout << "Hello world!" << endl;return 0; }?
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