Recover it!
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Recover it!
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https://codeforces.com/contest/1176/problem/D
題解:線性篩+暴力
/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int #define endl "\n" using namespace std; typedef long long ll; //typedef __int128 lll; const int N=4000000+10; const int M=100000+10; const int MOD=1e9+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,p,l,r,u,v; int ans,cnt,flag,temp,sum; int a[N],b[N],c[N]; int prime[N]; int pre[N]; int maxd[N]; char str; struct node{}; int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endif//ios::sync_with_stdio(false);//cin.tie(0);//cout.tie(0);//scanf("%d",&t);//while(t--){prime[0]=prime[1]=1;for(int i=2;i<N;i++){if(!prime[i]){pre[++cnt]=i;maxd[i]=i;}for(int j=1;j<=cnt&&i*pre[j]<N;j++){prime[i*pre[j]]=1;maxd[i*pre[j]]=min(maxd[i],maxd[pre[j]]);if(i%pre[j]==0)break;}}scanf("%d",&n);for(int i=1;i<=2*n;i++){scanf("%d",&a[i]),b[a[i]]++;}sort(a+1,a+2*n+1,greater<int>());for(int i=1;i<=2*n;i++){if(prime[a[i]]&&b[a[i]]&&b[a[i]/maxd[a[i]]]){b[a[i]/maxd[a[i]]]--;b[a[i]]--;c[++sum]=a[i];//cout<<a[i]<<endl;}else if(!prime[a[i]]&&a[i]<=199999&&b[a[i]]&&b[pre[a[i]]]){b[pre[a[i]]]--;//cout<<a[i]<<" "<<pre[a[i]]<<endl;;b[a[i]]--;c[++sum]=a[i];}//cout<<sum<<" "<<i<<endl;}for(int i=1;i<=n;i++){printf("%d%c",c[i]," \n"[i==n]);}//}#ifdef DEBUGprintf("Time cost : %lf s\n",(double)clock()/CLOCKS_PER_SEC); #endif//cout << "Hello world!" << endl;return 0; }?
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