Almost All Divisors
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Almost All Divisors
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https://codeforces.com/contest/1165/problem/D
題解:給定的數(shù)組是答案的除1和本身以外所有因子,求答案
題解:貪心
答案=最大值*最小值
因子可能有多或者少;
/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int #define endl "\n" using namespace std; typedef long long ll; //typedef __int128 lll; const int N=100000+10; const int M=100000+10; const int MOD=1e9+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,p,l,r,u,v; ll ans,cnt,flag,temp,sum; ll a[N]; char str; struct node{}; int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endif//ios::sync_with_stdio(false);//cin.tie(0);//cout.tie(0);scanf("%d",&t);while(t--){scanf("%d",&n);ll maxl=-INF;ll minl=INF;for(int i=1;i<=n;i++){scanf("%I64d",&a[i]);maxl=max(a[i],maxl);minl=min(a[i],minl);}ans=maxl*minl;sort(a+1,a+n+1);int sqr=sqrt(ans);cnt=0;for(int i=2;i<=sqr;i++){if(ans%i==0){int x=lower_bound(a+1,a+n+1,ans/i)-a;int y=lower_bound(a+1,a+n+1,i)-a;//cout<<x<<endl;if(x>n||x<1||y>n||y<1||a[x]!=ans/i||a[y]!=i){ans=-1;break;}cnt++;if((ll)i*i!=ans){cnt++;}}}cout<<(cnt==n?ans:-1)<<endl;}#ifdef DEBUGprintf("Time cost : %lf s\n",(double)clock()/CLOCKS_PER_SEC); #endif//cout << "Hello world!" << endl;return 0; }?
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