Cat Party
(Easy Edition)
https://codeforces.com/contest/1163/problem/B1
(Hard Edition)
https://codeforces.com/contest/1163/problem/B2
題解:
C++版本一
/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int #define endl "\n" using namespace std; typedef long long ll; //typedef __int128 lll; const int N=100000+10; const int M=100000+10; const int MOD=1e9+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,p,l,r,u,v; int ans,cnt,flag,temp,sum; int a[N]; int b[N]; int c[N]; char str; struct node{}; int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endif//ios::sync_with_stdio(false);//cin.tie(0);//cout.tie(0);//scanf("%d",&t);while(~scanf("%d",&n)){ans=1;sum=0;for(int i=1;i<=n;i++){scanf("%d",&a[i]);if(b[a[i]]==0)sum++;c[b[a[i]]]--;b[a[i]]++;c[b[a[i]]]++;if(sum==1){ans=i;continue;}if(c[1]==1){if(i==1||sum==1){continue;}if(c[(i-1)/(sum-1)]==sum-1)ans=i;continue;}if(c[1]==sum){ans=i;continue;}if(i%sum==1&&c[i/sum]==sum-1&&c[i/sum+1]==1)ans=i;}cout<<ans<<endl;}#ifdef DEBUGprintf("Time cost : %lf s\n",(double)clock()/CLOCKS_PER_SEC); #endif//cout << "Hello world!" << endl;return 0; }?
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