https://codeforces.com/contest/1156/problem/A

題解：模擬

1、注意3 1 2這種排列；

/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int #define endl "\n" using namespace std; typedef long long ll; //typedef __int128 lll; const int N=100000+10; const int M=100000+10; const int MOD=1e9+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,p,l,r,u,v; int ans,cnt,flag,temp,sum; int a[N]; char str; struct node{}; int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endif//ios::sync_with_stdio(false);//cin.tie(0);//cout.tie(0);//scanf("%d",&t);//while(t--){scanf("%d",&n);for(int i=1;i<=n;i++){scanf("%d",&a[i]);}for(int i=2;i<=n;i++){if(a[i-1]==a[i]){cout<<"Infinite"<<endl;return 0;}if(a[i-1]==1){if(a[i]==2){ans+=3;}else{ans+=4;}}else if(a[i-1]==2){if(a[i]==1){ans+=3;}else{cout<<"Infinite"<<endl;return 0;}}else{if(a[i]==1){ans+=4;}else{cout<<"Infinite"<<endl;return 0;}}}for(int i=3;i<=n;i++){if(a[i-2]==3&&a[i-1]==1&&a[i]==2){ans--;}}cout<<"Finite"<<endl;cout<<ans<<endl;//}#ifdef DEBUGprintf("Time cost : %lf s\n",(double)clock()/CLOCKS_PER_SEC); #endif//cout << "Hello world!" << endl;return 0; }

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