Two Merged Sequences
生活随笔
收集整理的這篇文章主要介紹了
Two Merged Sequences
小編覺得挺不錯的,現在分享給大家,幫大家做個參考.
https://codeforces.com/contest/1144/problem/G
題解:我抄的,但是
a[i]<a[i+1]這個為什么啊??? 做了一些測試,感覺可以證明。
/* *@Author: STZG *@Language: C++ */ #include <bits/stdc++.h> #include<iostream> #include<algorithm> #include<cstdlib> #include<cstring> #include<cstdio> #include<string> #include<vector> #include<bitset> #include<queue> #include<deque> #include<stack> #include<cmath> #include<list> #include<map> #include<set> //#define DEBUG #define RI register int #define endl "\n" using namespace std; typedef long long ll; //typedef __int128 lll; const int N=200000+10; const int M=100000+10; const int MOD=1e9+7; const double PI = acos(-1.0); const double EXP = 1E-8; const int INF = 0x3f3f3f3f; int t,n,m,k,p,l,r,u,v; int cnt,flag,temp,sum; int a[N]; char str; struct node{}; int main() { #ifdef DEBUGfreopen("input.in", "r", stdin);//freopen("output.out", "w", stdout); #endif//ios::sync_with_stdio(false);//cin.tie(0);//cout.tie(0);//scanf("%d",&t);//while(t--){scanf("%d",&n);for(int i=1;i<=n;i++)scanf("%d",&a[i]);vector<int>v1={-1};vector<int>v2={INF};vector<int>ans;for(int i=1;i<=n;i++){u=v1.back()<a[i];v=v2.back()>a[i];if(u&&v){if(i+1<=n){if(a[i]<a[i+1]){v1.push_back(a[i]);ans.push_back(0);}else{v2.push_back(a[i]);ans.push_back(1);}}else{v1.push_back(a[i]);ans.push_back(0);}}else if(u||v){if(u){v1.push_back(a[i]);ans.push_back(0);}else{v2.push_back(a[i]);ans.push_back(1);}}else{flag=1;break;}}if(!flag){cout<<"YES"<<endl;for(int i:ans)cout<<i<<' ';}else{cout<<"NO"<<endl;}//}#ifdef DEBUGprintf("Time cost : %lf s\n",(double)clock()/CLOCKS_PER_SEC); #endif//cout << "Hello world!" << endl;return 0; }?
總結
以上是生活随笔為你收集整理的Two Merged Sequences的全部內容,希望文章能夠幫你解決所遇到的問題。
- 上一篇: Graph Without Long D
- 下一篇: Prepared for New Acm