最近在寫一個項目 項目中 涉及到數(shù)組差集問題 代碼如下

$arr1 = [

[

"cardId" => 1010284722,

"beforeAmounts" => 100,

"afterAmounts" => 20,

"diffAmounts" => -80,

"diffStatus" => 1

],

[

"cardId" => 1010284722,

"beforeAmounts" => 100,

"afterAmounts" => 200,

"diffAmounts" => 100,

"diffStatus" => 0

],

[

"cardId" => 177561410,

"beforeAmounts" => 2000,

"afterAmounts" => 1000,

"diffAmounts" => -1000,

"diffStatus" => 1

],

[

"cardId" => 177561410,

"beforeAmounts" => 2000,

"afterAmounts" => 1000,

"diffAmounts" => -1000,

"diffStatus" => 1

],

[

"cardId" => 1077060068,

"beforeAmounts" => 789,

"afterAmounts" => 100,

"diffAmounts" => -689,

"diffStatus" => 1

],

[

"cardId" => 1077060068,

"beforeAmounts" => 789,

"afterAmounts" => 100,

"diffAmounts" => -689,

"diffStatus" => 1

]

];

$arr2 = [

[

"cardId" => 177561410,

"beforeAmounts" => 2000,

"afterAmounts" => 1000,

"diffAmounts" => -1000,

"diffStatus" => 1

],

[

"cardId" => 1077060068,

"beforeAmounts" => 789,

"afterAmounts" => 100,

"diffAmounts" => -689,

"diffStatus" => 1

]

];

echo 'arr1個數(shù):'.count($arr1).'
';

echo 'arr1集合: ';

var_dump($arr1);

echo '

---

';

echo 'arr2個數(shù):'.count($arr2).'
';

echo 'arr2集合: ';

var_dump($arr2);

echo '

---

';

//這是我求差集的方法

foreach($arr1 as $k=>$v) if(in_array($v, $arr2)) unset($arr1[$k]);

echo '差集個數(shù):'.count($arr1).'
';

echo '差集集合：';

var_dump($arr1);

因為有重復的數(shù)據(jù) 這樣求出來之后 差集的個數(shù) + $arr2 的個數(shù) 不等于 $arr1 的個數(shù)

問 ： 怎么樣求差集才能

差集的個數(shù) + $arr2 的個數(shù) = $arr1 的個數(shù)

而且最后求出的差集 集合也包含那兩個重復的數(shù)組元素 "cardId" => 177561410 和 "cardId" => 1077060068

總結

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