牛客练习赛24题解（搜索，DP）
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牛客练习赛24题解（搜索，DP）
小編覺得挺不錯的,現在分享給大家,幫大家做個參考.
A題，C題不講，基礎題（但是我要抨擊一下這次比賽，卡cin,cout，卡的太狠了，根本就不讓過的那種，QAQ）
鏈接：https://www.nowcoder.com/acm/contest/157/B
來源：牛客網
空間限制：C/C++ 262144K，其他語言524288K
64bit IO Format: %lld
題目描述
????鳳凰于飛，翙翙其羽，亦集爰止。
——《詩經·卷阿》????傳說，鳳凰是百鳥之王。有一天，鳳凰要召開百鳥大會，百鳥國是一個由n個節點組成的樹，每個節點有一只鳥，開會的節點定在1號節點。每只鳥可以花費1s通過一條邊，由于每根樹枝(邊)的載重有限，只允許一只鳥同時通過。作為會議的策劃師，HtBest想知道百鳥國的所有鳥在1點集合最少需要多少秒。
輸入描述:
第一行有一個正整數n，表示百鳥國節點個數。接下來n-1行，第i行兩個正整數a i,b i用空格隔開，表示樹上節點a i,b i之間有一條邊。
輸出描述:
第一行一個整數，表示集合最少需要的時間。 示例1輸入
復制 3 1 2 2 3輸出
復制 2 示例2輸入
復制 3 1 2 1 3輸出
復制 1 示例3輸入
復制 4 1 2 2 3 2 4輸出
復制 3備注:
對于100%的測試數據：1 ≤ n ≤ 1000000
數據量較大，注意使用更快的輸入輸出方式。
解析：有人是用搜索過的，我的第一想法就是并查集了（收獲了并查集大佬的寫法，也是蠻開心的，然后要注意的就是不要連接與起點有關的任何點）
，這樣對于任何分枝就都能連接起來，起到+1的作用， 1 /** 2 3 :;LaEaHKEEGpPXU7;, 4 .:75pKH11252U252XapZgRQgD6XJscLr;,. 5 :LXpRgGaX521JLw1JswJJsJs22XHPPEZEGDOMMRDOa7. 6 .r2EDDZEpZPZP6KpHX5SXH5XXa5KwaXaSX5UJ1c77sLs2GMQQ6r . 7 ,LpgOGpEZGZEZEpZKpHHU5wP5HEDgpXpHa2SSa5aSXULr7rrirrJXRBp; ;B 8 ,J6MRZH6EgEEZE6E6EZZPZXXwSSGQXr::aPpP5USUHaHaKa5Lvrr7ri;rLHBB2: Kc 9 rpQDOpPPOGGZOGOZG6GEOEOEDPPGBa. .PaSSUXSUUUaUSaKXKS177r7rrrirSBBR7 .O, 10 :UBQOKPK6ZOOOEDEO6GZE6EpEpDgDBR: UBpXHa5aSaUS5SUS5XapPHJc7rrv7rr7sgBBs .g. 11 ;gBMPXpO6GEOEOEOEGEOEE6EZEEDRGBB EB5pKSXpHKaHSX552S5aUHHEX17c7vr7777s5RBS: .R; 12 .sQBPXpDZOODOgODGOGgEDEOEOGgGgOOMB: LBKKSXSHa52aaKXHXKaa5aSaaHXSJLcL7vcc777JDBBg2;. Qi 13 ;2ggp2EDDOggGEDGgDDOgGGZDOOZOGg6gEBX vBZaHUKaaUXXXSXXKXpXHXH5wwaa52U1wssLsLJccv1UDQBQ67. O7 14 :ZZUU5PROOEOZOZGGOODZOGgODZOOgOggRgRB; ;:..R6XaKKpP6PGppKPHpHpPX5aU21UUa5Sw52UwUJJv77L77sSpQMDU; ;B5 15 ,SRJ7sSHGggEOZOEG6OODpOZgggOQQBBBBBQBBQ.,;;. 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LBBgGgZHsr;vrr;rcXpP5UUS5X5S2XS5SS1URBggpEZgDDGOGggRD 57 ,;irrs2KgQRPJJJSUXKXSHJpBM . . . ZBBOUsr;:. ,,,rHgZPUaSaUSUSSXaUPXsSBB6ZZp6EEGOOGDEggO 58 ;BBQQZaSJ5J15SJDQ7 .iEBL:. . .,:,:;SRQGZXPXXSHaS2UUSUSswQB6OZgG6pZZGODEOGDE 59 JgUri1aGEpEpXSS5LBQ, .rLap2Jr ;712OO6ZggRDZXHXpKK2211LLLc7wgBa2PODRGE6OZgDgGDGD 60 7QB; ,Jc76DaZXOZgDPEBBX, :c1HEZ1c;:,.,:;cHDgQQggMZgGOZO6OEGpXsLLsJXHPOBBBc;vss5EMggZDODOgED6 61 LZJ::iwrrr72EPgXU5OBBBBBBBp7: .i5P6wL;, .:LS6DMgMgZKgEOPOGGDDGEXULvLSOBBBBBQBgDQDJ5rrr7JOQQDDZGEgDD 62 wp rR5, .HQRX7r72RQBBBBBQBMEK6Uc7sc7cHOU:, .:LHgOQg6ZOPZpZGGEDERZPwcr7LKDDaJr:. rBX;;:r:ir1DBQMgRgDp 63 7D,sw: , Z. .LgBBQBBOsJaQBBBBBBXrr. .:rwZBBQgROgDgDOERRMgROOScrLsPP5r, 7Qs,::::::rUgRgZOG6 64 ,Q57:r ,: ,r U: .;; .vL7L;r:UG7.:sr;JSgQBgDEZXXUSXpHa21svr7r7s2v:. iQK...:,:::;LLJJws 65 OBHs;. :;;,v H: :6X; rpL;7pSrrr7r;::,....,,:;iirrvvvr, :BBPs;;:,,,,::;:: 66 ::rPDEL:..7:c;7r pK .: :KL.:r:.. ..:icsS5sr:,. JgGgBQDOSJss77r 67 :r;::: , PH r, ,;5: ,::::;7Ls7Lc7;: ,:7JP17rJUs 68 .:J: :; .,:K6BQS7:.,.,. 69 :r7Ji;r7;::;;. 70 . **/ 71 72 #include <iostream> 73 #include <algorithm> 74 #include <vector> 75 #include <stdlib.h> 76 #include <string.h> 77 #include <math.h> 78 #include <queue> 79 #include <stdio.h> 80 using namespace std; 81 82 #define FFI(a, b) for(int i = a; i < b; i++) 83 #define FFJ(a, b) for(int j = a; j < b; j++) 84 #define FFK(a, b) for(int k = a; k < b; k++) 85 #define RR(a, b) for(int i = a; i > b; i++) 86 #define ME(a, b) memset(a, b, sizeof(a)) 87 #define SC(x) scanf("%d", &x) 88 #define SCC(a, b) scanf("%d%d", &a, &b) 89 #define SCCC(a, b, c) scanf("%d%d%d", &a, &b, &c) 90 #define PR(x) printf("%d\n", x) 91 #define PRR(a, b) printf("%d%d\n", a, b); 92 #define INF 0x3f3f3f3f 93 #define MAX 1314520 94 #define MOD 1000000007 95 #define E 2.71828182845 96 #define M 8 97 #define N 6 98 typedef long long LL; 99 const double PI = acos(-1.0); 100 typedef pair<int, int> Author; 101 vector<pair<string, int> > VP; 102 103 /*******************************************************************************************************************************************************/ 104 //QAQ，我就說是并查集，為什么不相信我，QAQ 105 int pre[MAX], num[MAX]; 106 //int Find(int t){ 107 // int ret = t; 108 // while(pre[t] != t) t = pre[t]; 109 // 110 // while(t != pre[ret]){ 111 // int temp = pre[ret]; 112 // pre[ret] = t; 113 // ret = temp; 114 // } 115 // return t; 116 //} 117 118 int Find(int t){return t == pre[t] ? t : pre[t] = Find(pre[t]);} //比我寫的牛逼多了，orz 119 int main(void){ 120 #ifdef Empirefree 121 freopen("in.txt", "r", stdin); 122 freopen("out.txt", "w", stdout); 123 #endif 124 125 ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); 126 int n, a, b, x, y, ans; 127 128 cin>>n;ME(num, 0);ans = 0; 129 FFI(1, n + 1) pre[i] = i; 130 FFI(1, n){ 131 cin>>x>>y; 132 a = Find(x);b = Find(y); 133 if(x != 1 && y != 1) pre[a] = b; //這里最重要，除去原點，防止連接成直線 134 } 135 FFI(2, n + 1) num[Find(i)]++; 136 137 cout<< *max_element(num + 1, num + n + 1)<<endl; 138 139 return EXIT_SUCCESS; 140 } Empirefree.top
鏈接：https://www.nowcoder.com/acm/contest/157/D
來源：牛客網
空間限制：C/C++ 32768K，其他語言65536K
64bit IO Format: %lld
題目描述
一年一度的山東省oi夏令營又開始了，每到這個季節，山東的oier們都會歡聚這里，一起學（tuí）習（feì）。當然，為了能更加愉快地學（tuí）習（feì），就少不了要自帶電腦，用電便開始成了一種問題，于是便有一種神奇的數據結構誕生了！這就是山東省oi專用數據結構——插排樹（如圖）小K為了能更好的學（tuí）習（feì），所以他想盡量的往后做，所以現在請你幫幫他，他最遠可以離講臺多遠。 已知插排樹的根節點在講臺上，有且僅有一個根節點（根節點入度為0），最遠距離即所有插排的長度，小K電腦線的長度忽略不計
本題良心大樣例下載地址： https://kench.co/tree.zip
輸入描述:
第一行一個整數n表示有n個節點然后n-1行，每行三個整數a,b,c，表示插排a是接在插排b上的，插排a的長度為c
輸出描述:
一個整數n表示最遠距離 示例1輸入
復制 9 2 1 2 3 1 2 4 1 1 5 2 3 6 2 1 7 3 1 8 3 4 9 7 5輸出
復制 8說明
1=>3=>7=>9備注:
對于30%的數據 n<233對于70%的數據 n<2333
對于100%的數據 n<50000
c小于20
a,b小于等于n
解析：對于每個點，暴力搜索一下，每次保留最大值 1 /** 2 3 :;LaEaHKEEGpPXU7;, 4 .:75pKH11252U252XapZgRQgD6XJscLr;,. 5 :LXpRgGaX521JLw1JswJJsJs22XHPPEZEGDOMMRDOa7. 6 .r2EDDZEpZPZP6KpHX5SXH5XXa5KwaXaSX5UJ1c77sLs2GMQQ6r . 7 ,LpgOGpEZGZEZEpZKpHHU5wP5HEDgpXpHa2SSa5aSXULr7rrirrJXRBp; ;B 8 ,J6MRZH6EgEEZE6E6EZZPZXXwSSGQXr::aPpP5USUHaHaKa5Lvrr7ri;rLHBB2: Kc 9 rpQDOpPPOGGZOGOZG6GEOEOEDPPGBa. .PaSSUXSUUUaUSaKXKS177r7rrrirSBBR7 .O, 10 :UBQOKPK6ZOOOEDEO6GZE6EpEpDgDBR: UBpXHa5aSaUS5SUS5XapPHJc7rrv7rr7sgBBs .g. 11 ;gBMPXpO6GEOEOEOEGEOEE6EZEEDRGBB EB5pKSXpHKaHSX552S5aUHHEX17c7vr7777s5RBS: .R; 12 .sQBPXpDZOODOgODGOGgEDEOEOGgGgOOMB: LBKKSXSHa52aaKXHXKaa5aSaaHXSJLcL7vcc777JDBBg2;. Qi 13 ;2ggp2EDDOggGEDGgDDOgGGZDOOZOGg6gEBX vBZaHUKaaUXXXSXXKXpXHXH5wwaa52U1wssLsLJccv1UDQBQ67. O7 14 :ZZUU5PROOEOZOZGGOODZOGgODZOOgOggRgRB; ;:..R6XaKKpP6PGppKPHpHpPX5aU21UUa5Sw52UwUJJv77L77sSpQMDU; ;B5 15 ,SRJ7sSHGggEOZOEG6OODpOZgggOQQBBBBBQBBQ.,;;. 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LBBgGgZHsr;vrr;rcXpP5UUS5X5S2XS5SS1URBggpEZgDDGOGggRD 57 ,;irrs2KgQRPJJJSUXKXSHJpBM . . . ZBBOUsr;:. ,,,rHgZPUaSaUSUSSXaUPXsSBB6ZZp6EEGOOGDEggO 58 ;BBQQZaSJ5J15SJDQ7 .iEBL:. . .,:,:;SRQGZXPXXSHaS2UUSUSswQB6OZgG6pZZGODEOGDE 59 JgUri1aGEpEpXSS5LBQ, .rLap2Jr ;712OO6ZggRDZXHXpKK2211LLLc7wgBa2PODRGE6OZgDgGDGD 60 7QB; ,Jc76DaZXOZgDPEBBX, :c1HEZ1c;:,.,:;cHDgQQggMZgGOZO6OEGpXsLLsJXHPOBBBc;vss5EMggZDODOgED6 61 LZJ::iwrrr72EPgXU5OBBBBBBBp7: .i5P6wL;, .:LS6DMgMgZKgEOPOGGDDGEXULvLSOBBBBBQBgDQDJ5rrr7JOQQDDZGEgDD 62 wp rR5, .HQRX7r72RQBBBBBQBMEK6Uc7sc7cHOU:, .:LHgOQg6ZOPZpZGGEDERZPwcr7LKDDaJr:. rBX;;:r:ir1DBQMgRgDp 63 7D,sw: , Z. .LgBBQBBOsJaQBBBBBBXrr. .:rwZBBQgROgDgDOERRMgROOScrLsPP5r, 7Qs,::::::rUgRgZOG6 64 ,Q57:r ,: ,r U: .;; .vL7L;r:UG7.:sr;JSgQBgDEZXXUSXpHa21svr7r7s2v:. iQK...:,:::;LLJJws 65 OBHs;. :;;,v H: :6X; rpL;7pSrrr7r;::,....,,:;iirrvvvr, :BBPs;;:,,,,::;:: 66 ::rPDEL:..7:c;7r pK .: :KL.:r:.. ..:icsS5sr:,. JgGgBQDOSJss77r 67 :r;::: , PH r, ,;5: ,::::;7Ls7Lc7;: ,:7JP17rJUs 68 .:J: :; .,:K6BQS7:.,.,. 69 :r7Ji;r7;::;;. 70 . **/ 71 72 #include <iostream> 73 #include <algorithm> 74 #include <vector> 75 #include <stdlib.h> 76 #include <string.h> 77 #include <math.h> 78 #include <queue> 79 #include <stdio.h> 80 using namespace std; 81 82 #define FFI(a, b) for(int i = a; i < b; i++) 83 #define FFJ(a, b) for(int j = a; j < b; j++) 84 #define FFK(a, b) for(int k = a; k < b; k++) 85 #define RR(a, b) for(int i = a; i > b; i++) 86 #define ME(a, b) memset(a, b, sizeof(a)) 87 #define SC(x) scanf("%d", &x) 88 #define SCC(a, b) scanf("%d%d", &a, &b) 89 #define SCCC(a, b, c) scanf("%d%d%d", &a, &b, &c) 90 #define PR(x) printf("%d\n", x) 91 #define PRR(a, b) printf("%d%d\n", a, b); 92 #define INF 0x3f3f3f3f 93 #define MAX 55555 94 #define MOD 1000000007 95 #define E 2.71828182845 96 #define M 8 97 #define N 6 98 typedef long long LL; 99 const double PI = acos(-1.0); 100 typedef pair<int, int> Author; 101 /*******************************************************************************************************************************************************/ 102 vector<Author> VP[MAX]; 103 int dis[MAX], ans; 104 105 void DFS(int index, int sum){ 106 int len = VP[index].size(); 107 108 ans = max(ans, sum); 109 FFI(0, len)DFS(VP[index][i].first, sum + VP[index][i].second); 110 111 } 112 int main(void){ 113 #ifdef Empirefree 114 freopen("in.txt", "r", stdin); 115 freopen("out.txt", "w", stdout); 116 #endif 117 118 ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); 119 int n, a, b, c; 120 121 SC(n);ME(dis, 0);ans = 0; 122 FFI(1, n){ 123 SCCC(a, b, c); 124 //b插在a上，且從b開始搜索 125 VP[b].push_back(make_pair(a, c)); 126 dis[a] = 1; 127 } 128 FFI(1, n + 1)if(!dis[i])DFS(i, 0); 129 PR(ans); 130 131 return EXIT_SUCCESS; 132 } Empirefree.top
鏈接：https://www.nowcoder.com/acm/contest/157/E
來源：牛客網
空間限制：C/C++ 32768K，其他語言65536K
64bit IO Format: %lld
題目描述
有一只可愛的老青蛙，在路的另一端發現了一個黑的東西，想過去一探究竟。于是便開始踏上了旅途 一直這個小路上有很多的隧道，從隧道的a進入，會從b出來，但是隧道不可以反向走。 這只青蛙因為太老了，所以很懶，現在想請你幫幫慢，問他最少需要幾步才可以到達對面。 將小徑看作一條數軸，青蛙初始在0上，這只青蛙可以向前跳也可以向后跳，但每次只能跳一格，每跳一格記作一步，從隧道進到隧道出算做一步。輸入描述:
第一行兩個數m,n；表示黑色物品在數軸m點上，數軸上總共有n個隧道接下來n行，每行a，b兩個數，表示從a進會從b出
10 <= m,n <= 233
0<a,b<=m
輸出描述:
一個數ans表示最小步數 示例1輸入
復制 16 4 2 10 8 15 12 5 13 6輸出
復制 7說明
0-->1-->2-->10-->9-->8-->15-->16 解析：這題最TM有意思，和今年（2018）湘潭F題maze一樣，只不過變成了一維平面，下面介紹2種解法，DFS和BFS（最后自己用DFS重新做了一下湘潭的F題，TLE，難受，以后最短路還是得用BFS） 1 /** 2 3 :;LaEaHKEEGpPXU7;, 4 .:75pKH11252U252XapZgRQgD6XJscLr;,. 5 :LXpRgGaX521JLw1JswJJsJs22XHPPEZEGDOMMRDOa7. 6 .r2EDDZEpZPZP6KpHX5SXH5XXa5KwaXaSX5UJ1c77sLs2GMQQ6r . 7 ,LpgOGpEZGZEZEpZKpHHU5wP5HEDgpXpHa2SSa5aSXULr7rrirrJXRBp; ;B 8 ,J6MRZH6EgEEZE6E6EZZPZXXwSSGQXr::aPpP5USUHaHaKa5Lvrr7ri;rLHBB2: Kc 9 rpQDOpPPOGGZOGOZG6GEOEOEDPPGBa. .PaSSUXSUUUaUSaKXKS177r7rrrirSBBR7 .O, 10 :UBQOKPK6ZOOOEDEO6GZE6EpEpDgDBR: UBpXHa5aSaUS5SUS5XapPHJc7rrv7rr7sgBBs .g. 11 ;gBMPXpO6GEOEOEOEGEOEE6EZEEDRGBB EB5pKSXpHKaHSX552S5aUHHEX17c7vr7777s5RBS: .R; 12 .sQBPXpDZOODOgODGOGgEDEOEOGgGgOOMB: LBKKSXSHa52aaKXHXKaa5aSaaHXSJLcL7vcc777JDBBg2;. Qi 13 ;2ggp2EDDOggGEDGgDDOgGGZDOOZOGg6gEBX vBZaHUKaaUXXXSXXKXpXHXH5wwaa52U1wssLsLJccv1UDQBQ67. 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JgGgBQDOSJss77r 67 :r;::: , PH r, ,;5: ,::::;7Ls7Lc7;: ,:7JP17rJUs 68 .:J: :; .,:K6BQS7:.,.,. 69 :r7Ji;r7;::;;. 70 . **/ 71 72 #include <iostream> 73 #include <algorithm> 74 #include <vector> 75 #include <stdlib.h> 76 #include <string.h> 77 #include <math.h> 78 #include <queue> 79 #include <stdio.h> 80 using namespace std; 81 82 #define FFI(a, b) for(int i = a; i < b; i++) 83 #define FFJ(a, b) for(int j = a; j < b; j++) 84 #define FFK(a, b) for(int k = a; k < b; k++) 85 #define RR(a, b) for(int i = a; i > b; i++) 86 #define ME(a, b) memset(a, b, sizeof(a)) 87 #define SC(x) scanf("%d", &x) 88 #define SCC(a, b) scanf("%d%d", &a, &b) 89 #define SCCC(a, b, c) scanf("%d%d%d", &a, &b, &c) 90 #define PR(x) printf("%d\n", x) 91 #define PRR(a, b) printf("%d%d\n", a, b); 92 #define INF 0x3f3f3f3f 93 #define MAX 234 94 #define MOD 1000000007 95 #define E 2.71828182845 96 #define M 8 97 #define N 6 98 typedef long long LL; 99 const double PI = acos(-1.0); 100 typedef pair<int, int> Author; 101 vector<pair<string, int> > VP; 102 103 /*******************************************************************************************************************************************************/ 104 vector<int> vec[MAX]; 105 int dis[MAX], n; 106 void DFS(int index, int sum){ 107 int len; 108 109 dis[index] = sum; 110 len = vec[index].size(); 111 if(index <= n && dis[index + 1] > sum + 1)DFS(index + 1, sum + 1); 112 if(index - 1 >= 0 && dis[index - 1] > sum + 1)DFS(index - 1, sum + 1); 113 FFI(0, len)if(dis[vec[index][i]] > sum + 1)DFS(vec[index][i], sum + 1); 114 } 115 int main(void){ 116 #ifdef Empirefree 117 freopen("in.txt", "r", stdin); 118 freopen("out.txt", "w", stdout); 119 #endif 120 121 ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); 122 int m, a, b; 123 124 cin>>n>>m;ME(dis, INF); 125 FFI(0, m){ 126 cin>>a>>b; 127 vec[a].push_back(b); 128 } 129 130 DFS(0, 0); 131 cout<<dis[n]<<endl; 132 return EXIT_SUCCESS; 133 } Empirefree.top的DFS 1 /** 2 3 :;LaEaHKEEGpPXU7;, 4 .:75pKH11252U252XapZgRQgD6XJscLr;,. 5 :LXpRgGaX521JLw1JswJJsJs22XHPPEZEGDOMMRDOa7. 6 .r2EDDZEpZPZP6KpHX5SXH5XXa5KwaXaSX5UJ1c77sLs2GMQQ6r . 7 ,LpgOGpEZGZEZEpZKpHHU5wP5HEDgpXpHa2SSa5aSXULr7rrirrJXRBp; ;B 8 ,J6MRZH6EgEEZE6E6EZZPZXXwSSGQXr::aPpP5USUHaHaKa5Lvrr7ri;rLHBB2: Kc 9 rpQDOpPPOGGZOGOZG6GEOEOEDPPGBa. .PaSSUXSUUUaUSaKXKS177r7rrrirSBBR7 .O, 10 :UBQOKPK6ZOOOEDEO6GZE6EpEpDgDBR: UBpXHa5aSaUS5SUS5XapPHJc7rrv7rr7sgBBs .g. 11 ;gBMPXpO6GEOEOEOEGEOEE6EZEEDRGBB EB5pKSXpHKaHSX552S5aUHHEX17c7vr7777s5RBS: .R; 12 .sQBPXpDZOODOgODGOGgEDEOEOGgGgOOMB: LBKKSXSHa52aaKXHXKaa5aSaaHXSJLcL7vcc777JDBBg2;. 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KL::JGBBBgE6Hp6XMQ; . ... ,2s ,,,,:::::,:::::::,,.:sQQB2 ;DHa5U52S2U25USJ 45 a: :7;1BB2 .v, sL;LPQgDBPH6KPQBpGBG . ... .. aP:. .. ,::,:::::,,,,.;rSgBQDa; :gSSwSUUU525US2U 46 5; ;;r2QBB, .s: :a7:PBZ2,:BEaZPKgBZOgB, . ...:LEHri::,:.,,.,,,::rsXRBgGKEJi, 2GH252SUS5S11wH5 47 U: ;:rwDBBr .c, rB6r 167.,,RQPpEP6OpKEBc ., . : ::sS7;cKB6HHa1XOQRRQBRgEZDBH; .. ;RZUPSSU525USSpK2 48 s; ;::aBg, .; .Gv,H::,,::,;BQDOGHPXpKBs .,. . .,. .r:;:6gOEBQRRRDggQgOHgMGL, .;PEHHXaaKaPXPKPaXS 49 s7.:,sBa :..S, vE::::; 7BBMgZH6pQBr . ,:, ,.,r2RHSSpMZPKRRZpgggav, ;UpEZaaaKHHUHPPaUJHGO 50 a;.775: .::rU. gR:,:. :;:BBBBQar . ,, ,.,7rggJwU6DDGMgOGgXc:, ,rPGOpKSXSXSKUKHU1UHgOEP 51 1i :SZJrLXpBBMRB: .v Ba,. :sv: . irsBUSpEEGPPpg65r:..,;sKZDZHSX5XaHU55K2wUGMRZ6Z6 52 :K :7asvwc2MgEQB, :gg.:iB7 .,,,:. ...,. . .. .:iM6GEpSSXZOEs:...;spZpKKXXSX5Xa5Ja5wwKGQDEpp6OZ 53 w; ,LXLr77sLwL5aR. gRgQgaQBi ,vJwvi,. .;;:;7: . . ,... rRDRJUSXpgas:,.:;U66SaHa2X5aUa552X12SgQgpZpEpGOD 54 H: ;XJ;77rv7rJUaQ;rgaPgXXHBB; . . .ri:;; ,: . :6QZEKHXpXXL:,::r1PKXaa2XSS5a5S5UJ22aOBgEpOppZOOgG 55 iwsJsr7rsLrrLcJ2gQGXHwa1SUHBB: . ... . .., : 1BRKpOEGp2Jr;::rsXP1Uaa2U5a5aUa5SsSpgQRZGZEEZZOOgDg 56 ,cs5aXaP552ssLwRSHXaSS5asXBB. . . . LBBgGgZHsr;vrr;rcXpP5UUS5X5S2XS5SS1URBggpEZgDDGOGggRD 57 ,;irrs2KgQRPJJJSUXKXSHJpBM . . . ZBBOUsr;:. ,,,rHgZPUaSaUSUSSXaUPXsSBB6ZZp6EEGOOGDEggO 58 ;BBQQZaSJ5J15SJDQ7 .iEBL:. . .,:,:;SRQGZXPXXSHaS2UUSUSswQB6OZgG6pZZGODEOGDE 59 JgUri1aGEpEpXSS5LBQ, .rLap2Jr ;712OO6ZggRDZXHXpKK2211LLLc7wgBa2PODRGE6OZgDgGDGD 60 7QB; ,Jc76DaZXOZgDPEBBX, :c1HEZ1c;:,.,:;cHDgQQggMZgGOZO6OEGpXsLLsJXHPOBBBc;vss5EMggZDODOgED6 61 LZJ::iwrrr72EPgXU5OBBBBBBBp7: .i5P6wL;, .:LS6DMgMgZKgEOPOGGDDGEXULvLSOBBBBBQBgDQDJ5rrr7JOQQDDZGEgDD 62 wp rR5, .HQRX7r72RQBBBBBQBMEK6Uc7sc7cHOU:, .:LHgOQg6ZOPZpZGGEDERZPwcr7LKDDaJr:. rBX;;:r:ir1DBQMgRgDp 63 7D,sw: , Z. .LgBBQBBOsJaQBBBBBBXrr. .:rwZBBQgROgDgDOERRMgROOScrLsPP5r, 7Qs,::::::rUgRgZOG6 64 ,Q57:r ,: ,r U: .;; .vL7L;r:UG7.:sr;JSgQBgDEZXXUSXpHa21svr7r7s2v:. iQK...:,:::;LLJJws 65 OBHs;. :;;,v H: :6X; rpL;7pSrrr7r;::,....,,:;iirrvvvr, :BBPs;;:,,,,::;:: 66 ::rPDEL:..7:c;7r pK .: :KL.:r:.. ..:icsS5sr:,. JgGgBQDOSJss77r 67 :r;::: , PH r, ,;5: ,::::;7Ls7Lc7;: ,:7JP17rJUs 68 .:J: :; .,:K6BQS7:.,.,. 69 :r7Ji;r7;::;;. 70 . **/ 71 72 #include <iostream> 73 #include <algorithm> 74 #include <vector> 75 #include <stdlib.h> 76 #include <string.h> 77 #include <math.h> 78 #include <queue> 79 #include <stdio.h> 80 using namespace std; 81 82 #define FFI(a, b) for(int i = a; i < b; i++) 83 #define FFJ(a, b) for(int j = a; j < b; j++) 84 #define FFK(a, b) for(int k = a; k < b; k++) 85 #define RR(a, b) for(int i = a; i > b; i++) 86 #define ME(a, b) memset(a, b, sizeof(a)) 87 #define SC(x) scanf("%d", &x) 88 #define SCC(a, b) scanf("%d%d", &a, &b) 89 #define SCCC(a, b, c) scanf("%d%d%d", &a, &b, &c) 90 #define SCCCC(a, b, c, d) scanf("%d%d%d%d", &a, &b, &c, &d) 91 #define PR(x) printf("%d\n", x) 92 #define PRR(a, b) printf("%d%d\n", a, b); 93 #define INF 0x3f3f3f3f 94 #define MAX 333 95 #define MOD 1000000007 96 #define E 2.71828182845 97 #define M 8 98 #define N 6 99 typedef long long LL; 100 const double PI = acos(-1.0); 101 typedef pair<int, int> Author; 102 vector<pair<string, int> > VP; 103 104 /*******************************************************************************************************************************************************/ 105 int dis[MAX][MAX];char matrix[MAX][MAX]; 106 struct Node{ 107 int x; 108 int y; 109 int time; 110 }bn, en, temp1, temp2; 111 vector<Node> vec[MAX][MAX]; 112 int n, m, q; 113 bool Check(int x, int y){ 114 if(x >= 0 && x < n && y >= 0 && y < m && matrix[x][y] != '#') return true; 115 else return false; 116 } 117 void DFS(int x,int y, int sum){ 118 int len; 119 120 dis[x][y] = sum; 121 if(Check(x + 1, y) && dis[x + 1][y] > sum + 1) DFS(x + 1, y, sum + 1); 122 if(Check(x - 1, y) && dis[x - 1][y] > sum + 1) DFS(x - 1, y, sum + 1); 123 if(Check(x, y + 1) && dis[x][y + 1] > sum + 1) DFS(x, y + 1, sum + 1); 124 if(Check(x, y - 1) && dis[x][y - 1] > sum + 1) DFS(x, y - 1, sum + 1); 125 len = vec[x][y].size(); 126 FFI(0, len){ 127 if(Check(vec[x][y][i].x, vec[x][y][i].y) && dis[vec[x][y][i].x][vec[x][y][i].y] > sum + 3) 128 DFS(vec[x][y][i].x, vec[x][y][i].y, sum + 3); 129 } 130 } 131 void Clear(){ 132 133 FFI(0, n) 134 FFJ(0, m) 135 vec[i][j].clear(); 136 } 137 int main(void){ 138 #ifdef Empirefree 139 freopen("in.txt", "r", stdin); 140 freopen("out.txt", "w", stdout); 141 #endif 142 143 ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); 144 int a, b, c, d; 145 146 while(SCCC(n, m, q)){ 147 ME(dis, INF);Clear(); 148 FFI(0, n){ 149 150 scanf("%s", matrix[i]); 151 FFJ(0, m){ 152 if(matrix[i][j] == 'S') bn.x = i,bn.y = j; 153 if(matrix[i][j] == 'T') en.x = i,en.y = j; 154 } 155 } 156 FFI(0, q){ 157 SCCCC(a, b, c, d); 158 temp1.x = c;temp1.y = d; 159 vec[a][b].push_back(temp1); 160 } 161 DFS(bn.x, bn.y, 0); 162 if(dis[en.x][en.y] == INF) PR(-1); 163 else PR(dis[en.x][en.y]); 164 } 165 return EXIT_SUCCESS; 166 } maze的DFS超時代碼鏈接：https://www.nowcoder.com/acm/contest/157/F
來源：牛客網
空間限制：C/C++ 262144K，其他語言524288K
64bit IO Format: %lld
題目描述
小k有一個三輪，它最多可以裝105大小的東西小k有n種商品，他要準備出攤了
每種商品體積為vi，都有105件 輸出湊成1~m的體積的總方案數 輸出可能會很大，請對大質數19260817取模
輸入描述:
第一行兩個整數n,m，接下來n行，每行一個數代表v i
輸出描述:
一個數ans表示總方案數 示例1輸入
復制 2 8 1 3輸出
復制 17說明
從1~m體積的方案數分別為：1
1
2
2
2
3
3
3
備注:
不要忘記取模！！！n,m,v i?<= 50000 解析：完全背包，QAQ
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LBBgGgZHsr;vrr;rcXpP5UUS5X5S2XS5SS1URBggpEZgDDGOGggRD 57 ,;irrs2KgQRPJJJSUXKXSHJpBM . . . ZBBOUsr;:. ,,,rHgZPUaSaUSUSSXaUPXsSBB6ZZp6EEGOOGDEggO 58 ;BBQQZaSJ5J15SJDQ7 .iEBL:. . .,:,:;SRQGZXPXXSHaS2UUSUSswQB6OZgG6pZZGODEOGDE 59 JgUri1aGEpEpXSS5LBQ, .rLap2Jr ;712OO6ZggRDZXHXpKK2211LLLc7wgBa2PODRGE6OZgDgGDGD 60 7QB; ,Jc76DaZXOZgDPEBBX, :c1HEZ1c;:,.,:;cHDgQQggMZgGOZO6OEGpXsLLsJXHPOBBBc;vss5EMggZDODOgED6 61 LZJ::iwrrr72EPgXU5OBBBBBBBp7: .i5P6wL;, .:LS6DMgMgZKgEOPOGGDDGEXULvLSOBBBBBQBgDQDJ5rrr7JOQQDDZGEgDD 62 wp rR5, .HQRX7r72RQBBBBBQBMEK6Uc7sc7cHOU:, .:LHgOQg6ZOPZpZGGEDERZPwcr7LKDDaJr:. rBX;;:r:ir1DBQMgRgDp 63 7D,sw: , Z. .LgBBQBBOsJaQBBBBBBXrr. .:rwZBBQgROgDgDOERRMgROOScrLsPP5r, 7Qs,::::::rUgRgZOG6 64 ,Q57:r ,: ,r U: .;; .vL7L;r:UG7.:sr;JSgQBgDEZXXUSXpHa21svr7r7s2v:. iQK...:,:::;LLJJws 65 OBHs;. :;;,v H: :6X; rpL;7pSrrr7r;::,....,,:;iirrvvvr, :BBPs;;:,,,,::;:: 66 ::rPDEL:..7:c;7r pK .: :KL.:r:.. ..:icsS5sr:,. JgGgBQDOSJss77r 67 :r;::: , PH r, ,;5: ,::::;7Ls7Lc7;: ,:7JP17rJUs 68 .:J: :; .,:K6BQS7:.,.,. 69 :r7Ji;r7;::;;. 70 . **/ 71 72 #include <iostream> 73 #include <algorithm> 74 #include <vector> 75 #include <stdlib.h> 76 #include <string.h> 77 #include <math.h> 78 #include <queue> 79 #include <stdio.h> 80 using namespace std; 81 82 #define FFI(a, b) for(int i = a; i < b; i++) 83 #define FFJ(a, b) for(int j = a; j < b; j++) 84 #define FFK(a, b) for(int k = a; k < b; k++) 85 #define RR(a, b) for(int i = a; i > b; i++) 86 #define ME(a, b) memset(a, b, sizeof(a)) 87 #define SC(x) scanf("%d", &x) 88 #define SCC(a, b) scanf("%d%d", &a, &b) 89 #define SCCC(a, b, c) scanf("%d%d%d", &a, &b, &c) 90 #define PR(x) printf("%d\n", x) 91 #define PRR(a, b) printf("%d%d\n", a, b); 92 #define INF 0x3f3f3f3f 93 #define MAX 52000 94 #define MOD 19260817 95 #define E 2.71828182845 96 #define M 8 97 #define N 6 98 typedef long long LL; 99 const double PI = acos(-1.0); 100 typedef pair<int, int> Author; 101 vector<pair<string, int> > VP; 102 int read() 103 { 104 int x=0,f=1; char ch; 105 while (ch=getchar(),ch<'0'||ch>'9') if (ch=='-') f=-1; 106 while (x=x*10+ch-'0',ch=getchar(),ch>='0'&&ch<='9'); 107 return x*f; 108 } 109 /*******************************************************************************************************************************************************/ 110 LL bag[MAX]; 111 int main(void){ 112 #ifdef Empirefree 113 freopen("in.txt", "r", stdin); 114 freopen("out.txt", "w", stdout); 115 #endif 116 117 ios::sync_with_stdio(false); cin.tie(0); cout.tie(0); 118 LL n, m, a, ans; 119 120 bag[0] = 1;ans = 0; 121 n = read(); m = read(); 122 FFI(0, n){ 123 a = read(); 124 FFJ(a, m + 1) 125 bag[j] = (bag[j] + bag[j - a]) % MOD; 126 } 127 FFI(1, m + 1) ans = (ans + bag[i]) % MOD; 128 printf("%lld\n", ans); 129 130 return EXIT_SUCCESS; 131 } Empirefree.top
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轉載于:https://www.cnblogs.com/meditation5201314/p/9460505.html
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