http://lavasoft.blog.51cto.com/62575/66953

Dom4j遍歷解析XML測試 近來老和XML打交道，不深挖不行了。。 這是一個Dom4j解析XML的例子，為做復雜遞歸處理前期所寫的例子。涵蓋了XML的解析方面大部分核心API。 環境： Dom4j-1.6.1 Dom4j解析需要XML需要的最小類庫為： dom4j-1.6.1.jar jaxen-1.1-beta-6.jar 目標： 解析一個xml，輸出所有的屬性和元素值。 測試代碼： XML文件： <?xml version="1.0" encoding="GBK"?>
<doc>
????<person id="1" sex="m">
????????<name>zhangsan</name>
????????<age>32</age>
????????<adds>
????????????<add code="home">home add</add>
????????????<add code="com">com add</add>
????????</adds>
????</person>
????<person id="2" sex="w">
????????<name>lisi</name>
????????<age>22</age>
????????<adds>
????????????<add ID="22" id="23" code="home">home add</add>
????????????<add ID="23" id="22" code="com">com add</add>
????????????<add id="24" code="com">com add</add>
????????</adds>
????</person>
</doc> 解析代碼： package com.topsoft.test;

import org.dom4j.io.SAXReader;
import org.dom4j.Document;
import org.dom4j.DocumentException;
import org.dom4j.Element;
import org.dom4j.Node;

import java.util.Iterator;
import java.util.List;
import java.io.InputStream;

/**
* Created by IntelliJ IDEA.<br>
* <b>User</b>: leizhimin<br>
* <b>Date</b>: 2008-3-26 15:53:51<br>
* <b>Note</b>: Dom4j遍歷解析XML測試
*/
public class TestDom4j {
????/**
???? * 獲取指定xml文檔的Document對象,xml文件必須在classpath中可以找到
???? *
???? * @param xmlFilePath xml文件路徑
???? * @return Document對象
???? */
????public static Document parse2Document(String xmlFilePath) {
????????SAXReader reader = new SAXReader();
????????Document document = null;
????????try {
????????????InputStream in = TestDom4j.class.getResourceAsStream(xmlFilePath);
????????????document = reader.read(in);
????????} catch (DocumentException e) {
????????????System.out.println(e.getMessage());
????????????System.out.println("讀取classpath下xmlFileName文件發生異常，請檢查CLASSPATH和文件名是否存在！");
????????????e.printStackTrace();
????????}
????????return document;
????}

????public static void testParseXMLData(String xmlFileName) {
????????//產生一個解析器對象
????????SAXReader reader = new SAXReader();
????????//將xml文檔轉換為Document的對象
????????Document document = parse2Document(xmlFileName);
????????//獲取文檔的根元素
????????Element root = document.getRootElement();
????????//定義個保存輸出xml數據的緩沖字符串對象
????????StringBuffer sb = new StringBuffer();
????????sb.append("通過Dom4j解析XML,并輸出數據:\n");
????????sb.append(xmlFileName + "\n");
????????sb.append("----------------遍歷start----------------\n");
????????//遍歷當前元素(在此是根元素)的子元素
????????for (Iterator i_pe = root.elementIterator(); i_pe.hasNext();) {
????????????Element e_pe = (Element) i_pe.next();
????????????//獲取當前元素的名字
????????????String person = e_pe.getName();
????????????//獲取當前元素的id和sex屬性的值并分別賦給id,sex變量
????????????String id = e_pe.attributeValue("id");
????????????String sex = e_pe.attributeValue("sex");
????????????String name = e_pe.element("name").getText();
????????????String age = e_pe.element("age").getText();
????????????//將數據存放到緩沖區字符串對象中
????????????sb.append(person + ":\n");
????????????sb.append("\tid=" + id + " sex=" + sex + "\n");
????????????sb.append("\t" + "name=" + name + " age=" + age + "\n");

????????????//獲取當前元素e_pe(在此是person元素)下的子元素adds
????????????Element e_adds = e_pe.element("adds");
????????????sb.append("\t" + e_adds.getName() + "\n");

????????????//遍歷當前元素e_adds(在此是adds元素)的子元素
????????????for (Iterator i_adds = e_adds.elementIterator(); i_adds.hasNext();) {
????????????????Element e_add = (Element) i_adds.next();
????????????????String code = e_add.attributeValue("code");
????????????????String add = e_add.getTextTrim();
????????????????sb.append("\t\t" + e_add.getName() + ":" + " code=" + code + " value=\"" + add + "\"\n");
????????????}
????????????sb.append("\n");
????????}
????????sb.append("-----------------遍歷end-----------------\n");
????????System.out.println(sb.toString());


????????System.out.println("---------通過XPath獲取一個元素----------");
????????Node node1 = document.selectSingleNode("/doc/person");
????????System.out.println("輸出節點:" +
????????????????"\t"+node1.asXML());

????????Node node2 = document.selectSingleNode("/doc/person/@sex");
????????System.out.println("輸出節點:" +
????????????????"\t"+node2.asXML());

????????Node node3 = document.selectSingleNode("/doc/person[name=\"zhangsan\"]/age");
????????System.out.println("輸出節點:" +
????????????????"\t"+node3.asXML());

????????System.out.println("\n---------XPath獲取List節點測試------------");
????????List list = document.selectNodes("/doc/person[name=\"zhangsan\"]/adds/add");
????????for(Iterator it=list.iterator();it.hasNext();){
????????????Node nodex=(Node)it.next();
????????????System.out.println(nodex.asXML());
????????}

????????System.out.println("\n---------通過ID獲取元素的測試----------");
????????System.out.println("陷阱：通過ID獲取，元素ID屬性名必須為“大寫ID”，小寫的“id”會認為是普通屬性！");
????????String id22 = document.elementByID("22").asXML();
????????String id23 = document.elementByID("23").asXML();
????????String id24 = null;
????????if (document.elementByID("24") != null) {
????????????id24 = document.elementByID("24").asXML();
????????} else {
????????????id24 = "null";
????????}

????????System.out.println("id22=??" + id22);
????????System.out.println("id23=??" + id23);
????????System.out.println("id24=??" + id24);
????}


????public static void main(String args[]) {
????????testParseXMLData("/person.xml");
????}
} 運行結果： 通過Dom4j解析XML,并輸出數據:
/person.xml
----------------遍歷start----------------
person:
????id=1 sex=m
????name=zhangsan age=32
????adds
??add: code=home value="home add"
??add: code=com value="com add"

person:
????id=2 sex=w
????name=lisi age=22
????adds
??add: code=home value="home add"
??add: code=com value="com add"
??add: code=com value="com add"

-----------------遍歷end-----------------

---------通過XPath獲取一個元素----------
輸出節點:????<person id="1" sex="m">
????????<name>zhangsan</name>
????????<age>32</age>
????????<adds>
????????????<add code="home">home add</add>
????????????<add code="com">com add</add>
????????</adds>
????</person>
輸出節點:????sex="m"
輸出節點:????<age>32</age>

---------XPath獲取List節點測試------------
<add code="home">home add</add>
<add code="com">com add</add>

---------通過ID獲取元素的測試----------
陷阱：通過ID獲取，元素ID屬性名必須為“大寫ID”，小寫的“id”會認為是普通屬性！
id22=??<add ID="22" id="23" code="home">home add</add>
id23=??<add ID="23" id="22" code="com">com add</add>
id24=??null

Process finished with exit code 0
發個Idea7開發界面截圖: 點擊圖片放大 想從頭了解dom4j的朋友可以看dom4j文檔中的quick start，這個是E文版的，另外有熱心的網友已經將自己翻譯的中文版奉獻出來了，可以看看： [url]http://www.java3z.com/cwbwebhome/article/article2/2296.html?id=837[/url]

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