C++求数组子数组和的最大值并将该子数组和最大值打印出来
#include <iostream>
using namespace std;
void GetMaxValue(int *pDatas, int len);
void main()
{
?int datas1[6] = {1, -2, 3, 5, -3, 2};
?//輸出子數組最大值為8
?//該子數組為:3 5;
?GetMaxValue(datas1, 6);
?//輸出子數組最大值為:9
??? //該子數組為:3 5 -1 2
?int datas2[6] = {0, -2, 3, 5, -1, 2};
?GetMaxValue(datas2, 6);
?//輸出子數組最大值為:-2
?//該子數組為: -2
?int datas3[6] = {-9, -2, -3, -5, -3};
?GetMaxValue(datas3, 5);
?int tem;
?cin >> tem;
}
void GetMaxValue(int *pDatas, const int len)
{
?int max = -1000;
?int sum = 0;
?int k = 0;
?int *result = new int[len];//該數組用于保存結果的子數組集合
?int *tem = new int[len];//該數組用于輔助
?for(int q = 0; q < len; q++)
?{
??result[q] = -100;
??tem[q] = -100;
?}
?bool isChanged = false;
?for(int i =0; i < len; i++)
?{
??sum =0;
??for(int q =0; q < len; q++)
??{
???tem[q] = -100;
??}
??isChanged = false;
??for(int j = i; j < len; j++)
??{
???sum += pDatas[j];
???tem[j] = pDatas[j];
???if(sum > max)
???{
????max = sum;
????k = j;
????isChanged = true;
???}
??}
??if(isChanged)
??{
???for(int p = k + 1; p < len; p++)
???{
????tem[p] = -100;
???}
???for(int q = 0;q < len;q++)
???{
????result[q] = -100;
???}
???for(int f =0; f < len; f++)
???{
????if(tem[f] != -100 )
????{
?????result[f] = tem[f];
????}
???}
??}
?}
?cout << "子數組和最大值為:" << max << endl;
?cout << "該子數組為:" << endl;
?for(int i = 0;i < len; i++)
?{
??if(result[i] != -100)
??{
???cout << result[i] <<"? ";
??}??
?}
?cout << endl;
}
轉載于:https://www.cnblogs.com/ganquanfu2008/archive/2013/06/13/3133398.html
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