解決 java.lang.RuntimeException: Method i in android.util.Log not mocked. See http://g.co/androidstudio/not-mocked for details.

• • 1. 原因
  • 2. 解決

1. 原因

Android SDK 中測(cè)試一個(gè) Json 不會(huì)消耗哪些本不必要的資源.

2. 解決

添加包

testImplementation 'org.json:json:20201115'

自定義一個(gè) JsonUtils 文件

package com.ykenan.alipay.util;import org.json.JSONArray; import org.json.JSONException; import org.json.JSONObject;import java.util.ArrayList; import java.util.HashMap; import java.util.Iterator; import java.util.List; import java.util.Map;public class JsonUtils {public Map<String, Object> parse(String jsonStr) {Map<String, Object> result = null;if (null != jsonStr) {try {JSONObject jsonObject = new JSONObject(jsonStr);result = parseJSONObject(jsonObject);} catch (JSONException e) {// TODO Auto-generated catch blocke.printStackTrace();}} // if (null != jsonStr)return result;}private Object parseValue(Object inputObject) throws JSONException {Object outputObject = null;if (null != inputObject) {if (inputObject instanceof JSONArray) {outputObject = parseJSONArray((JSONArray) inputObject);} else if (inputObject instanceof JSONObject) {outputObject = parseJSONObject((JSONObject) inputObject);} else if (inputObject instanceof String || inputObject instanceof Boolean || inputObject instanceof Integer) {outputObject = inputObject;}}return outputObject;}private List<Object> parseJSONArray(JSONArray jsonArray) throws JSONException {List<Object> valueList = null;if (null != jsonArray) {valueList = new ArrayList<>();for (int i = 0; i < jsonArray.length(); i++) {Object itemObject = jsonArray.get(i);if (null != itemObject) {valueList.add(parseValue(itemObject));}} // for (int i = 0; i < jsonArray.length(); i++)} // if (null != valueStr)return valueList;}private Map<String, Object> parseJSONObject(JSONObject jsonObject) throws JSONException {Map<String, Object> valueObject = null;if (null != jsonObject) {valueObject = new HashMap<>();Iterator<String> keys = jsonObject.keys();while (keys.hasNext()) {String keyStr = keys.next();Object itemObject = jsonObject.opt(keyStr);if (null != itemObject) {valueObject.put(keyStr, parseValue(itemObject));} // if (null != itemValueStr)} // while (keyStr.hasNext())} // if (null != valueStr)return valueObject;} }

測(cè)試

JsonUtils jsonUtils = new JsonUtils();System.out.println(jsonUtils.parse(jsonData).get("name"));

總結(jié)

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