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Given two strings?S?1???and?S?2??,?S=S?1???S?2???is defined to be the remaining string after taking all the characters in?S?2???from?S?1??. Your task is simply to calculate?S?1???S?2???for any given strings. However, it might not be that simple to do it?fast.

Input Specification:

Each input file contains one test case. Each case consists of two lines which gives?S?1???and?S?2??, respectively. The string lengths of both strings are no more than?10?4??. It is guaranteed that all the characters are visible ASCII codes and white space, and a new line character signals the end of a string.

Output Specification:

For each test case, print?S?1???S?2???in one line.

Sample Input:

They are students. aeiou

Sample Output:

Thy r stdnts.

3分：

getchar（）把第一個字符讀取了

#include <iostream> #include <string> using namespace std;string s1, s2; bool asc[256] = {false}; int main() {getline(cin,s1);getchar();getline(cin,s2);int len1 = s1.length(), len2 = s2.length();for(int i = 0; i < len2; i++){asc[s2[i]] = true;}for(int i = 0; i < len1; i++){if(asc[s1[i]] == true) continue;else printf("%c",s1[i]);}return 0; }

?20分：

#include <iostream> #include <string> using namespace std;string s1, s2; bool asc[256] = {false}; int main() {getline(cin,s1);getline(cin,s2);int len1 = s1.length(), len2 = s2.length();for(int i = 0; i < len2; i++){asc[s2[i]] = true;}for(int i = 0; i < len1; i++){if(asc[s1[i]] == true) continue;else printf("%c",s1[i]);}return 0; }

?

總結

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