java中开根号求三角形_Java编程 如何计算三角形的内切圆半径?
共回答了13個問題采納率:100%
一般三角形:r=2S/(a+b+c),其中S是三角形面積,a、b、c是三角形三邊.另外S=根號下p(p-a)(p-b)(p-c),其中p=(a+b+c)/2
public class Triple {
private double a;
private double b;
private double c;
public Triple(double a,double b,double c){
this.a = a;
this.b = b;
this.c = c;
}
public static void main(String[] args) {
double x1 = 0,y1 = 0;
double x2 = 0,y2 = 3;
double x3 = 4,y3 = 0;
Point pa = new Point(x1,y1);
Point pb = new Point(x2,y2);
Point pc = new Point(x3,y3);
double a = Point.distance(pc,pb);
double b = Point.distance(pa,pc);
double c = Point.distance(pa,pb);
Triple triple = new Triple(a,b,c);
double s = triple.area();
double r = triple.getInnerRadius();
System.out.println("Area is:" + s);;
System.out.println("Inner r is:" + r);
}
public double area(){
double p = (a + b + c) / 2;
return Math.sqrt(p*(p-a)*(p-b)*(p-c));
}
public double getInnerRadius(){
double s = area();
return 2 * s /(a+b+c);
}
}
class Point{
private double x;
private double y;
public Point(double x,double y){
this.x = x;
this.y = y;
}
public static double distance(Point p1,Point p2){
double square = Math.pow((p1.x - p2.x),2) + Math.pow((p2.y - p1.y),2); //(x1-x2)^2 + (y1-y2)^2
return Math.sqrt(square);
}
}
--------------用一個直角三角形測試
Area is:6.0
Inner r is:1.0
1年前
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