小編典典

查看是否可行：

try {

if (subjectString.matches(

"(?ix)\\A(?: # Anchor address\n" +

" (?: # Mixed\n" +

" (?:[A-F0-9]{1,4}:){6} # Non-compressed\n" +

" |(?=(?:[A-F0-9]{0,4}:){2,6} # Compressed with 2 to 6 colons\n" +

" (?:[0-9]{1,3}\\.){3}[0-9]{1,3} # and 4 bytes\n" +

" \\z) # and anchored\n" +

" (([0-9A-F]{1,4}:){1,5}|:)((:[0-9A-F]{1,4}){1,5}:|:) # and at most 1 double colon\n" +

" |::(?:[A-F0-9]{1,4}:){5} # Compressed with 7 colons and 5 numbers\n" +

" )\n" +

" (?:(?:25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9]?[0-9])\\.){3} # 255.255.255.\n" +

" (?:25[0-5]|2[0-4][0-9]|1[0-9][0-9]|[1-9]?[0-9]) # 255\n" +

"| # Standard\n" +

" (?:[A-F0-9]{1,4}:){7}[A-F0-9]{1,4} # Standard\n" +

"| # Compressed\n" +

" (?=(?:[A-F0-9]{0,4}:){0,7}[A-F0-9]{0,4} # Compressed with at most 7 colons\n" +

" \\z) # and anchored\n" +

" (([0-9A-F]{1,4}:){1,7}|:)((:[0-9A-F]{1,4}){1,7}|:) # and at most 1 double colon\n" +

"|(?:[A-F0-9]{1,4}:){7}:|:(:[A-F0-9]{1,4}){7} # Compressed with 8 colons\n" +

")/[A-F0-9]{0,4}\\z # Anchor address"))

{

// String matched entirely

} else {

// Match attempt failed

}

} catch (PatternSyntaxException ex) {

// Syntax error in the regular expression

}

大約一年前，我購買了一個(gè)非常有用的程序RegexMagic，用于計(jì)劃使用的一些復(fù)雜正則表達(dá)式。

假定它是Java，所以應(yīng)該編譯，我假設(shè)/ 60可以在0000和FFFF的范圍之間，您可以修改最后一部分。

/ [A-F0-9] {0,4}是我添加到正則表達(dá)式中以匹配您的示例的內(nèi)容。

2020-11-16

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