題目

Notice that the number 123456789 is a 9-digit number consisting exactly the numbers from 1 to 9, with no duplication. Double it we will obtain 246913578, which happens to be another 9-digit number consisting exactly the numbers from 1 to 9, only in a different permutation. Check to see the result if we double it again!

Now you are suppose to check if there are more numbers with this property. That is, double a given number with k digits, you are to tell if the resulting number consists of only a permutation of the digits in the original number.

Input Specification:

Each input contains one test case. Each case contains one positive integer with no more than 20 digits.

Output Specification:

For each test case, first print in a line “Yes” if doubling the input number gives a number that consists of only a permutation of the digits in the original number, or “No” if not. Then in the next line, print the doubled number.

Sample Input:

11234567899

Sample Output:

1

2Yes

2469135798

題解

思路

建立一個哈希表，存放每個字符出現的次數

將原數乘以2后，和哈希表每個字符出現的次數作對比

完事兒嗷

數據結構

_dict 是一個哈希表，對每個鍵默認值是0

鍵是0到9的字符

值是它出現的次數

算法

對作為字符串的原數，按照每一個字符出現的次數添加到哈希表

將原數乘以2,對每一個出現的字符，哈希表相應減一

如果哈希表不是每一項都為0,那么就說明是No

代碼

因為使用Python能AC，因此只放了Python的代碼。

1

2

3

4

5

6

7

8

9

10

11

12

13

14

15

16

17from collections import defaultdict

_dict = defaultdict(int)

a = input()

for i in a:

_dict[i] += 1

a = str(int(a) * 2)

for i in a:

_dict[i] -= 1

for i in "0123456789":

if _dict[i] != 0:

print("No")

break

else:

print("Yes")

print(a)

創作挑戰賽新人創作獎勵來咯，堅持創作打卡瓜分現金大獎

總結

以上是生活随笔為你收集整理的python大于小于1023python大于小于_PythonPAT 1023 Have Fun with Numbers的全部內容，希望文章能夠幫你解決所遇到的問題。

如果覺得生活随笔網站內容還不錯，歡迎將生活随笔推薦給好友。