【HDU - 4006】The kth great number (优先队列,求第k大的数)
題干:
Xiao Ming and Xiao Bao are playing a simple Numbers game. In a round Xiao Ming can choose to write down a number, or ask Xiao Bao what the kth great number is. Because the number written by Xiao Ming is too much, Xiao Bao is feeling giddy. Now, try to help Xiao Bao.
Input
There are several test cases. For each test case, the first line of input contains two positive integer n, k. Then n lines follow. If Xiao Ming choose to write down a number, there will be an " I" followed by a number that Xiao Ming will write down. If Xiao Ming choose to ask Xiao Bao, there will be a "Q", then you need to output the kth great number.?
Output
The output consists of one integer representing the largest number of islands that all lie on one line.?
Sample Input
8 3 I 1 I 2 I 3 Q I 5 Q I 4 QSample Output
1 2 3Hint
Xiao Ming won't ask Xiao Bao the kth great number when the number of the written number is smaller than k. (1=<k<=n<=1000000).解題報告:
? ? ?因為是動態插入數,所以不太好用線段樹(因為線段樹只建樹一次),如果是動態維護(或者說動態更新),那就考慮線段樹了。。。這題開一個優先隊列就可以了。跟這題對比一下【HDU - 4217 】Data Structure? (線段樹求第k小數)
AC代碼:
#include<bits/stdc++.h> using namespace std; priority_queue<int,vector<int >, greater<int> > pq; int main() {int q,k,tmp;char op[5];while(~scanf("%d%d",&q,&k) ) {while(!pq.empty() ) pq.pop();while(q--) {scanf("%s",op);if(op[0] == 'I') {scanf("%d",&tmp);pq.push(tmp);if(pq.size() > k) pq.pop();}else printf("%d\n",pq.top()); } } return 0 ;}?
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