題干：

There are?nn?points on the plane,?(x1,y1),(x2,y2),…,(xn,yn)(x1,y1),(x2,y2),…,(xn,yn).

You need to place an isosceles triangle with two sides on the coordinate axis to cover all points (a point is covered if it lies inside the triangle or on the side of the triangle). Calculate the minimum length of the shorter side of the triangle.

Input

First line contains one integer?nn?(1≤n≤1051≤n≤105).

Each of the next?nn?lines contains two integers?xixi?and?yiyi?(1≤xi,yi≤1091≤xi,yi≤109).

Output

Print the minimum length of the shorter side of the triangle. It can be proved that it's always an integer.

Examples

Input

3 1 1 1 2 2 1

Output

3

Input

4 1 1 1 2 2 1 2 2

Output

4

Note

Illustration for the first example:?

Illustration for the second example:?

解題報(bào)告：

? ? 這題比較巧妙的一個地方在于，要求次短邊的最小長度，其實(shí)也就是最長直角邊的最短長度（因?yàn)樾边吙隙ㄗ铋L）。所以既然要最短，那么等腰直角三角形，所以，，看代碼就理解了。

AC代碼：

#include<bits/stdc++.h> #define ll long long using namespace std;int main() {int n;cin>>n;ll ans = -1;int a,b;for(int i = 1; i<=n; i++) {scanf("%d%d",&a,&b);ans = max(ans,(ll)a+b);}cout << ans << endl;return 0; }

?

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