1、把圖轉(zhuǎn)化為程序能識(shí)別的鄰接矩陣；

2、理解圖的遍歷方法及對(duì)應(yīng)的生成樹。

二、使用儀器、器材

微機(jī)一臺(tái)

操作系統(tǒng)：Win10

編程軟件：C++

三、實(shí)驗(yàn)內(nèi)容及原理

1．圖的輸入：鄰接矩陣直接寫入源程序，或鍵盤輸入，或讀入數(shù)據(jù)文件

起始結(jié)點(diǎn)的輸入：運(yùn)行時(shí)由鍵盤輸入

輸出：生成樹的邊，用結(jié)點(diǎn)的序偶表示，

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• 實(shí)驗(yàn)過(guò)程原始數(shù)據(jù)記錄

GRAPH.H

#pragma once

//圖的鄰接表存儲(chǔ)結(jié)構(gòu)

#define INF 32767????????????? //定義∞

#define? MAXV 100????????????? //最大頂點(diǎn)個(gè)數(shù)

#define? MAX 100?????????????? ??? //最大全局?jǐn)?shù)組

#define MaxSize 100

typedef char InfoType;

typedef int ElemType;

typedef struct ANode

{

??? int adjvex;

??? struct ANode *nextarc;

??? int weight;

}ArcNode;

typedef struct Vnode

{

??? char info;

??? ArcNode *firstarc;

}VNode;

typedef struct

{

??? VNode adjlist[MAXV];

??? int n, e;

}AdjGraph;

//環(huán)形隊(duì)列

typedef struct

{

??? ElemType data[MaxSize];

??? int front, rear;????? //隊(duì)首和隊(duì)尾指針

} SqQueue;

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void CreateAdj(AdjGraph* &G, int A[MAXV][MAXV], int n, int e);//創(chuàng)建圖的鄰接表

void DispAdj(AdjGraph*G);//輸出鄰接表

void DestroyAdj(AdjGraph *&G);//銷毀鄰接表

void DFS(AdjGraph* G, int v);//深度優(yōu)先遍歷生成樹

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//---------------------------------------------------------

//--廣度優(yōu)先遍歷中使用隊(duì)列的基本運(yùn)算算法-------------------

//---------------------------------------------------------

void InitQueue(SqQueue *&q);

void DestroyQueue(SqQueue *&q);

bool QueueEmpty(SqQueue *q);

bool enQueue(SqQueue *&q, ElemType e);//進(jìn)棧

bool deQueue(SqQueue *&q, ElemType &e);

//---------------------------------------------------------

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void BFS(AdjGraph *G, int v);//廣度優(yōu)先遍歷生成樹

GRAPH.CPP

#include"pch.h"

#include "graph.h"

#include"malloc.h"

#include<iostream>

using namespace std;

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void CreateAdj(AdjGraph *& G, int A[MAXV][MAXV], int n, int e)

??? {

???????? int i, j; ArcNode *p;

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???????? for (i = 0; i < n; i++)????? //給鄰接表中所有頭節(jié)點(diǎn)指針置初值

???????? {

???????????? G->adjlist[i].firstarc = NULL;

???????? }

???????? for (i = 0; i < n; i++)????? //檢查鄰接矩陣每個(gè)元素

???????? {

???????????? for (j = n - 1; j >= 0; j--)

???????????? {

????????????????? if (A[i][j] != 0 && A[i][j] != INF)?? //存在一條邊

????????????????? {

????????????????????? p = (ArcNode*)malloc(sizeof(ArcNode));? //創(chuàng)建一個(gè)結(jié)點(diǎn)p

????????????????????? p->adjvex = j;?? //?? 存放鄰接點(diǎn)

????????????????????? p->weight = A[i][j];?? //存放權(quán)

????????????????????? p->nextarc = G->adjlist[i].firstarc;?? //頭插法

????????????????????? G->adjlist[i].firstarc = p;

????????????????? }

???????????? }

???????? }

???????? G->n = n; G->e = e;

}

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void DispAdj(AdjGraph * G)

{

??? int i;

??? ArcNode *p;

??? for (i = 0; i < G->n; i++)

??? {

???????? p = G->adjlist[i].firstarc;

???????? printf("%3d: ", i);

???????? while (p != NULL)

???????? {

???????????? printf("%3d[%d]→", p->adjvex, p->weight);

???????????? p = p->nextarc;

???????? }

???????? printf("∧\n");

??? }

}

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void DestroyAdj(AdjGraph *& G)

{

??? int i;

??? ArcNode *pre, *p;

??? for (i = 0; i < G->n; i++)???????? //掃描所有的單鏈表

??? {

???????? pre = G->adjlist[i].firstarc;? //p指向第i個(gè)單鏈表的首結(jié)點(diǎn)

???????? if (pre != NULL)

???????? {

???????????? p = pre->nextarc;

???????????? while (p != NULL)???????? //釋放第i個(gè)單鏈表的所有邊結(jié)點(diǎn)

???????????? {

????????????????? free(pre);

????????????????? pre = p; p = p->nextarc;

???????????? }

???????????? free(pre);

???????? }

??? }

??? free(G);?????????????????????? //釋放頭結(jié)點(diǎn)數(shù)組

}

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int? visited[MAX] = { 0 };

void DFS(AdjGraph* G, int v)?? //深度優(yōu)先遍歷

{

??? ArcNode*p;

??? visited[v] = 1;?? //置已訪問(wèn)標(biāo)記

??? //cout << v << endl;? //輸出被訪問(wèn)頂點(diǎn)的編號(hào)

??? p = G->adjlist[v].firstarc;? //p指向頂點(diǎn)v的第一個(gè)鄰接點(diǎn)

??? while (p != NULL)

??? {

???????? if (visited[p->adjvex] == 0)

???????? {

???????????? cout << "(" << v << "," << p->adjvex << ")" << endl;

???????????? DFS(G, p->adjvex);

???????? }

???????? p = p->nextarc;?? //p指向頂點(diǎn)v的下一個(gè)鄰接點(diǎn)

??? }

}

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void InitQueue(SqQueue *& q)

{

??? q = (SqQueue *)malloc(sizeof(SqQueue));

??? q->front = q->rear = 0;

}

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void DestroyQueue(SqQueue *& q)

{

??? free(q);

}

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bool QueueEmpty(SqQueue * q)

{

??? return(q->front == q->rear);

}

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bool enQueue(SqQueue *& q, ElemType e)

{

??? if ((q->rear + 1) % MaxSize == q->front)??? //隊(duì)滿上溢出

???????? return false;

??? q->rear = (q->rear + 1) % MaxSize;

??? q->data[q->rear] = e;

??? return true;

}

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bool deQueue(SqQueue *& q, ElemType & e)

{

??? if (q->front == q->rear)??????????????? //隊(duì)空下溢出

???????? return false;

??? q->front = (q->front + 1) % MaxSize;

??? e = q->data[q->front];

??? return true;

}

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void BFS(AdjGraph * G, int v)? //廣度優(yōu)先遍歷

{

??? int w, i;

??? ArcNode *p;

??? SqQueue *qu;??????????????????????????? //定義環(huán)形隊(duì)列指針

??? InitQueue(qu);????????????????????????????? //初始化隊(duì)列

??? int visited[MAXV];??????????? ????????? //定義頂點(diǎn)訪問(wèn)標(biāo)志數(shù)組

??? for (i = 0; i < G->n; i++) visited[i] = 0;?????? //訪問(wèn)標(biāo)志數(shù)組初始化

??? //printf("%2d ", v); ?????????????????????? //輸出被訪問(wèn)頂點(diǎn)的編號(hào)

??? visited[v] = 1;????????????? ?????????????? //置已訪問(wèn)標(biāo)記

??? enQueue(qu, v);

??? while (!QueueEmpty(qu))?????? ????????? //隊(duì)不空循環(huán)

??? {

???????? deQueue(qu, w);???????????????????????? //出隊(duì)一個(gè)頂點(diǎn)w

???????? p = G->adjlist[w].firstarc; ??????????? //指向w的第一個(gè)鄰接點(diǎn)

??? ??? while (p != NULL)?????????????????????? //查找w的所有鄰接點(diǎn)

???????? {

???????????? if (visited[p->adjvex] == 0) ????? //若當(dāng)前鄰接點(diǎn)未被訪問(wèn)

???????????? {

????????????????? cout << "(" << w << "," << p->adjvex << ")" << endl;

????????????????? //printf("%2d ", p->adjvex);? //訪問(wèn)該鄰接點(diǎn)

????????????????? visited[p->adjvex] = 1;??????? //置已訪問(wèn)標(biāo)記

????????????????? enQueue(qu, p->adjvex);??????? //該頂點(diǎn)進(jìn)隊(duì)

???????????? }

???????????? p = p->nextarc;????????????? ????? //找下一個(gè)鄰接點(diǎn)

???????? }

??? }

??? printf("\n");

}

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MAIN.CPP

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#include "pch.h"

#include <iostream>

#include"graph.h"

using namespace std;

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int main()

{

??? AdjGraph *G=new AdjGraph;

??? int A[MAXV][MAXV] = { {0,1,1,1,0,0,0,0,0,0,0},{1,0,0,0,1,1,0,0,0,0,0},

???????????? ????????????? {1,0,0,1,0,1,1,0,0,0,0},{1,0,1,0,0,0,0,1,0,0,0},

??? ????????????????????? {0,1,0,0,0,0,0,0,0,0,0},{0,1,1,0,0,0,0,0,0,0,0},

??? ????????????????????? {0,0,1,0,0,0,0,1,1,1,0},{0,0,0,1,0,0,1,0,0,0,1},

??? ??????????????? ??????{0,0,0,0,0,0,1,0,0,0,0},{0,0,0,0,0,0,1,0,0,0,0},

??? ????????????????????? {0,0,0,0,0,0,0,1,0,0,0} }

??? ;

??? int n = 11, e = 12;

??? CreateAdj(G, A, n, e);???????? //建立《教程》中圖8.1(a)的鄰接表

??? //printf("圖G的鄰接表:\n");

??? //DispAdj(G);????????????????? //輸出鄰接表G

??? cout << "請(qǐng)輸入起始結(jié)點(diǎn)" << endl;

??? int a;

??? cin >> a;

??? printf("深度優(yōu)先序列(遞歸)生成樹:"); printf("\n"); DFS(G, a); printf("\n");

??? printf("廣度優(yōu)先序列生成樹:"); printf("\n"); BFS(G, a); printf("\n");

??? DestroyAdj(G);???????????????? //銷毀鄰接表

??? return 1;

}

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五、實(shí)驗(yàn)結(jié)果及分析

從3出發(fā)，分別進(jìn)行深度優(yōu)先生成樹和廣度優(yōu)先生成樹。